What is func in this code block?

[sleepy hollow]

Apols if this is too basic, initially I thought func must be a reserved word in haskell.

when loaded and executed num3Times4 returns 12.

func appears to call times4.

is func a reserved word? how does this code know func is supposed to call times4 ?

------------------------------------------------------------------

times4 :: Int -> Int

times4 x = x * 4

doMult :: (Int -> Int) -> Int

doMult func = func 3

num3Times4 = doMult times4

--------------------------------------------------------------------

[sleepy hollow]

oh bah... realized the obvious.

the call by num3Times4 nominates a function to execute.
in this example I replaced func with foo to demonstrate func was not a reserved word.



------------------------------------------------------------------------

times4 :: Int -> Int

times4 x = x * 4

times5 :: Int -> Int

times5 x = x * 5

times6 :: Int -> Int

times6 x = x * 6

doMult :: (Int -> Int) -> Int

-- (internal function receives an Int, returns an Int)

-- function receives an Int & returns an Int

--doMult func = func 3

doMult foo = foo 3

num3Times4 = doMult times4

num3Times5 = doMult times5

num3Times6 = doMult times6

------------------------------------------------------------------