rounding off values

[Nikhanj]

Hi,

I have a number like this a=0.123456789. I want to round this value to two decimal places. How to do this in gremlin ????

[Michael Hunger]

it is groovy after all.

(0.452334D).round(2)

Am 09.10.2012 um 12:19 schrieb Nikhanj:

> Hi,
> I have a number like this a=0.123456789. I want to round this value to two decimal places. How to do this in gremlin ????
>

> --
>
>

[Nikhanj]

I tried but got  No signature of method: java.math.BigDecimal.round() is applicable for argument types: (java.lang.Integer) values: [2] 

[Nikhanj]

When i try this 0.12345.round(2), i get exception but on doing 0.12345D.round(2) i am able to get the result. Why so???

[Michael Hunger]

if you append a D it is a double.

for bigdecimals there is 

1.233434.setScale(2,BigDecimal.ROUND_HALF_UP)

--
 
 

[Nikhanj]

Thanks Michael!!! It works

[Marko Rodriguez]

Hi,

You can simply use:

Math.round(a);

gremlin> a=0.123456789

==>0.123456789

gremlin> Math.round(a)

==>0

To decide to what decimal you want, you can multiply and divide:

gremlin> Math.round(a * 100) / 100 ==>0.12

Note that Gremlin has full access to the Java and Groovy APIs, so:

http://stackoverflow.com/questions/153724/how-to-round-a-number-to-n-decimal-places-in-java

HTH,

Marko.

http://thinkaurelius.com

On Oct 9, 2012, at 4:19 AM, Nikhanj wrote:

Hi,

I have a number like this a=0.123456789. I want to round this value to two decimal places. How to do this in gremlin ????

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