Direction index in IPF of a base-centered monoclinic crystal structure

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Ryan Stone

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Apr 15, 2019, 12:08:47 AM4/15/19
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Please be as detailed as possible, explain what you want to do, what kind of data you are using. Attaching simplified code and data is always useful. Click the the button { } to inline code and finally remove these lines before posting :)

Dear expert:
I would like to get the direction index on the IPF of a base-centered monoclinic crystal structure.
When I run the following codes in MTEX 5.1.1 version, I can only get a IPF without a complete indexing (Please see the attached figure).
The code:
oM = ipfColorKey(grains);
oM.inversePoleFigureDirection = zvector;
plot(oM)

Information of the crystal:
CS = crystalSymmetry('12/m1', [13.4835 7.6626 5.1343], [90,127.78,90]*degree, 'X||a*', 'Y||b', 'Z||c', 'mineral', 'MnZn13', 'color', 'light blue');

Q1.JPG



Please tell me how to solve the problem.
Thank you!

sincerely,
Ryan

Luiz iMorales

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Apr 15, 2019, 1:18:27 AM4/15/19
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Hi


Would adding the 'noLabel' when plotting the colorkey and then use annotate([Miller(...) Miller()..],'symmetrised,'labeled')as suggested some days ago do what you want? 

+++

Luiz 
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Luiz iMorales

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Apr 15, 2019, 1:19:57 AM4/15/19
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Hi

Would adding the 'noLabel' when plotting the colorkey and then use annotate([Miller(...) Miller()..],'symmetrised,'labeled') as suggested some
Rüdiger

On Monday, April 15, 2019, Ryan Stone <ryans...@gmail.com> wrote:
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Ryan Stone

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Apr 15, 2019, 2:27:55 AM4/15/19
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Hi:
The mehtod works. However, there are still two problems.
My code is:
cs=crystalSymmetry('12/m1', [13.4835 7.6626 5.1343], [90,127.78,90]*degree, 'X||a*', 'Y||b', 'Z||c', 'mineral', 'MnZn13', 'color', 'light blue')
oM_MnZn13 = ipfColorKey(grains_MnZn13);
oM_MnZn13.inversePoleFigureDirection = zvector;
plot(oM_MnZn13, 'noLabel')
annotate([Miller(5,0,8,cs,'uvw')],'symmetrised','labeled')

Then, two problems:
1. I would like to get a figure in a right orientation. (see the attached figure)
2. I woule like to know what is the direction index at each corner. (see the attached figure)

Q1.JPG

Luiz iMorales

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Apr 15, 2019, 2:56:44 AM4/15/19
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hi

what if you try

plot(ipfKey,'landscape')

and for the poles of planes you use

(100), (010) (0-10) and (001) 'hkl'

Would that work?

best


Luiz



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