Re: how to plot texture fibres as function of Euler angle (phi1,phi,phi2)

[Ralf Hielscher]

Yes, MTEX can do so. The way is as follows:

Assume we have the Santa Fe sample ODF with cubic crystal symmetry

odf = SantaFe
cs = symmetry('cubic')

First define the Euler angles of the fibre

phi1 = linspace(0*degree,90*degree);
Phi  = 45*degree;
phi2 = 0*degree;

Next the corresponding orientations

ori =orientation('euler',ph1,Phi,phi2,cs)

In order to evaluate the ODF we use the function eval and plot the values against phi1

plot(phi1./degree,eval(odf,ori))

adjust axis limimts

xlim([0,90])
ylim([0,1.4])

The plot should look like this

Hope this helps,

Ralf.

[Nitesh Raj Jaladurgam]

Hi Ralf,

I have implemented the syntax suggested by you for plotting f(g) vs phi1, f(g) vs Phi and f(g) vs phi2. Unfortunately I end up with similar plots in all the three cases. My interest is to observe the intensity variations of ideal orientations(Cube, Goss, Brass, S and Copper) at different deformed conditions of sample.   

one more help!

Please suggest the syntax for calculating volume fraction of ideal orientations from ODF.

Thanks

Nitesh Raj

[Ralf Hielscher]

Given an odf the volume portion of a certain component, e.g. brass, is computed by

volume(odf,brassOrientation(odf.CS),10*degree) * 100 % result is in percent

The 10 degree gives the tolerance for the deviation from the ideal orientation.

Ralf