Defining main texture components ( copper, brass, S, cube and goss)

[saoussen ouhiba]

Hello,

I would like to determine volume fraction of main texture components(Cube, Goss, Copper, Brass and S) in a hot compressed aluminum alloy.

For example, Copper orientation = {112} <111> meaning that {112} is parallel to the rolling plane (RD,TD) and <111> is parallel to RD. In my case RD and TD are oriented as shown below. So {112} should be parallel to xz plane and <111> should be parallel to x axis.

However, if I define the copper orientation in mtex as in the following code, {112} will be parallel to xy plane. Can you help me please to define properly these texture components? I think that I need to rotate the sample reference frame 90° about x axis but I am not sure.

Thank you so much,

Saoussen

cs = ebsd('Aluminum').orientations.CS;
ss = specimenSymmetry('orthorhombic');

Copper = orientation.byMiller([1 1 2],[1 1 1],cs,ss);

[ruediger Kilian]

Hi,
have a look at this one:

copper = orientation.copper(cs,ss);

Cheers,
Rüdiger

[saoussen ouhiba]

Thank you for your suggestion. Unfortunately, I cannot use this predefined copper orientation because in this predefined copper orientation the first rotation of phi1 is about the z-axis, the second rotation of Phi is about the x-axis, and the third rotation of phi2 is about the z-axis. So the z-axis is considered as the ND in this predefined copper orientation. However, in my case, the y-axis is ND. So the first rotation should be around y-axis, the second one around x-axis and the third one around y-axis.

copper = orientation.copper(cs,ss)
 
copper = orientation (show methods, plot)
size: 1 x 1
crystal symmetry : Aluminum (m-3m)
specimen symmetry: mmm
 

Bunge Euler angles in degree
phi1  Phi phi2 Inv.

90   35   45    0

Thank you in advance for your help,

Saoussen

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[ruediger Kilian]

Hi,
TD,ND,RD do not exist in mtex as they are arbitrary characters assigned to x,y,z specimen directions. There are several Euler angle conventions supported such as ZYZ, ZXZ (most likely your default defined in the mtex_settings), Kocks or Canova.

Since you were asking for x || <111> and y || <112> why not use :

o = orientation.byEuler([35,90,45]*degree,cs);

Cheers,
Rüdiger

[saoussen ouhiba]

Hi Rüdiger,

Thank you for your explanation. As you suggested, I tried with Copper = orientation.byEuler([35,90,45]*degree,cs) and I plotted a 111 pole figure with mtex (the code shown below)

cs = ebsd('Aluminum').orientations.CS;

ss = ebsd('Aluminum').orientations.SS;
Copper = orientation('euler',[35,90,45]*degree,cs);
figure
plotPDF(Copper,Miller(1,1,1,cs),'antipodal')
annotate([xvector, yvector, zvector], 'label', {'RD','ND', 'TD'}, 'BackgroundColor', 'w');

I got the following 111 pole figure :                                 

How can I plot the same pole figure but with ND (y axis) out of plane as in the 111 pole figure below? The 111 pole figure below is taken from the literature and shows a typical 111 pole figure for a copper orientation. I think that I need to do a rotation of 90° about RD but I don't know how to formulate this in mtex.

Thank you so much for your help and sorry for bothering you again,

Saoussen 

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[wu jiang]

練帶什

saoussen ouhiba <saousse...@gmail.com> 于 2019年5月22日周三 下午8:19写道：

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[ruediger Kilian]

Hi,
like I said, the characters ND, TD, RD are for simply labels, such as 'X' for vector3d(1,0,0). You can define the specimen coordinate system using a direction of x and z axis where z is always orthogonal to the plane. There's no restriction in rotating your orientations within the specimen coordinates but if you have EBSD data, and you want ND to point out of the plane, simple label the zvector ND.
Cheers,
Rüdiger