Identify grains by their percentage of grain boundary to notIndexed area

[Sören T]

Hello,

For grain calculations I want to exclude all the Indexed grains with have a high share of grain boundaries touching the not Indexed area.

I have problems to create a grain specific value which tells me the share of the grain boundary length (Indexed,Indexed) to grain boundary length (Indexed,notIndexed).

So far I tried to get it with segLength but the matrix dimensions A and B vary of course in regard to each other and also in regard to the grain.id matrix

A = grainsNoInd.boundary('Indexed','Indexed').segLength;

B= grainsNoInd.boundary('Indexed','NotIndexed').segLength;

Somehow I need to get a matrix with one value for "length of (Indexed,Indexed)/(Indexed,notIndexed) grain boundaries" combined with the grainId

a working code somehow like 

"[grainsNoInd.id grainsNoInd.boundary('Indexed','Indexed').segLength]"

Has someone an idea?

[ruediger Kilian]

Hi,
have a look here for a start: https://groups.google.com/forum/#!topic/mtexmail/KJvA1d0KV88

Cheers,
Rüdiger

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[Sören T]

Perfect, thanks very much!

In the end it turned out like this:

%% Excluding grains with a certain percentage of indexed/notindexed boundary length

 

for i = 1:length(grains('indexed')) 

gbfrac(i)= sum(grains(i,'indexed').boundary('indexed','indexed').segLength)./ ... 

           sum(grains(i,'indexed').boundary.segLength); 

end

 

 

grains = grains('Indexed');

 

toRemove = grains(gbfrac<0.22);

 

grains(gbfrac<0.22)= []; 

 

 

clear toRemove

clear i

Am Mittwoch, 29. Mai 2019 11:19:12 UTC+2 schrieb ruediger Kilian:

Hi,
have a look here for a start: https://groups.google.com/forum/#!topic/mtexmail/KJvA1d0KV88

Cheers,
Rüdiger


> On 29 May 2019, at 10:26 AM, Sören T <soeren...@gmx.de> wrote:
>
> Hello,
>
> For grain calculations I want to exclude all the Indexed grains with have a high share of grain boundaries touching the not Indexed area.
>
> I have problems to create a grain specific value which tells me the share of the grain boundary length (Indexed,Indexed) to grain boundary length (Indexed,notIndexed).
>
> So far I tried to get it with segLength but the matrix dimensions A and B vary of course in regard to each other and also in regard to the grain.id matrix
>
> A = grainsNoInd.boundary('Indexed','Indexed').segLength;
>
> B= grainsNoInd.boundary('Indexed','NotIndexed').segLength;
>
>
> Somehow I need to get a matrix with one value for "length of (Indexed,Indexed)/(Indexed,notIndexed) grain boundaries" combined with the grainId
>
> a working code somehow like
>
> "[grainsNoInd.id grainsNoInd.boundary('Indexed','Indexed').segLength]"
>
> Has someone an idea?
>
> --
> If you want to reduce the number of emails you get through this forum login to https://groups.google.com/forum/?fromgroups=#!forum/mtexmail, click "My membership" and select "Don't send me email updates". You can still get emails on selected topics by staring them.
> ---
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> To unsubscribe from this group and stop receiving emails from it, send an email to mtex...@googlegroups.com.