Calling the same method with the same arguments but get different results.

[Theo]

Hi I want to call the same method with the same arguments multiple
times and get different results. A basic example is:

[Rule]
public var mocks:MockolateRule = new MockolateRule();

[Mock(type="strict")]
public var list:IList;

[Test]
public function test():void{

var seq:Sequence = sequence();
expecting(function ():void {

expect(list.getItemAt(0)).returns("Item1").thrice().inSequence(seq);
expect(list.getItemAt(0)).returns("Item2").inSequence(seq);
expect(list.getItemAt(0)).returns("Item3").inSequence(seq);
});

trace(list.getItemAt(0));
trace(list.getItemAt(0));
trace(list.getItemAt(0));

verify(list);
}

This results in:

Item1
Item2
Item2

And and error '1 unmet Exception'

I've tried a few alternatives such as:
expecting(function ():void {
expect(list.getItemAt(0)).returns("Item1").inSequence(seq);
expect(list.getItemAt(0)).returns("Item2").inSequence(seq);
expect(list.getItemAt(0)).returns("Item3").inSequence(seq);
});

and others to no avail. Surely I'm missing something simple here. This
seems like something that should be easy.

Thanks guys,

Theo.

[Theo]

Also posted on http://stackoverflow.com/ and got the answer see:

http://stackoverflow.com/questions/11312108/mockolate-calling-the-same-method-on-a-mock-with-the-same-arguments-but-return/11313164#11313164 

Basically instead of: 

expect(list.getItemAt(0)).returns("Item1").thrice().inSequence(seq); 
expect(list.getItemAt(0)).returns("Item2").inSequence(seq); 
expect(list.getItemAt(0)).returns("Item3").inSequence(seq);  

We need:

expect(list.getItemAt(0)).returns("Item1", "Item2", "Item3").thrice().inSequence(seq);  

[Kristopher Schultz]

This was also driving me crazy, so thank you! Too bad this is buried in the API docs. Really should be in the general documentation. I'd volunteer to write it!