Here are some of the rows of data in the database. The columns are
Parent_id, Page_num, external_id, index1, index2, index3, and name. The
rows I am interested in will all have the same Parent_id (10316). In the
sample data I did a query for rows where page_num > 1 (which is why you see
rows from 2 - 17). What I'd like to do is be able to return one row with
the highest page_num value (17).
Thanks.
Walter
Sample Data:
Parent_id Page_num external_id index1 index2 index3 name
10316 17 11542 K40397-1 4184840 8/14/2007 1756715
10316 16 11474 K40397-1 4184840 8/14/2007 1756715
10316 15 11473 K40397-1 4184840 8/14/2007 1756715
10316 14 11268 K40397-1 4184840 8/14/2007 1756715
10316 13 11142 K40397-1 4184840 8/14/2007 1756715
10316 12 11111 K40397-1 4184840 8/14/2007 1756715
10316 11 11110 K40397-1 4184840 8/14/2007 1756715
10316 10 11109 K40397-1 4184840 8/14/2007 1756715
10316 9 11108 K40397-1 4184840 8/14/2007 1756715
10316 8 11050 K40397-1 4184840 8/14/2007 1756715
10316 7 11043 K40397-1 4184840 8/14/2007 1756715
10316 6 11042 K40397-1 4184840 8/14/2007 1756715
10316 5 10994 K40397-1 4184840 8/14/2007 1756715
10316 4 10986 K40397-1 4184840 8/14/2007 1756715
10316 3 10985 K40397-1 4184840 8/14/2007 1756715
10316 2 10984 K40397-1 4184840 8/14/2007 1756715
> I have rows in a database that are grouped by a key value. They all
> have the same key value but some other columns on each row are not
> valued the same. How can I construct a query that will just return one
> row of the set with the highest value for one of the columns?
>
> Here are some of the rows of data in the database. The columns are
> Parent_id, Page_num, external_id, index1, index2, index3, and name. The
> rows I am interested in will all have the same Parent_id (10316). In
> the sample data I did a query for rows where page_num > 1 (which is why
> you see rows from 2 - 17). What I'd like to do is be able to return one
> row with the highest page_num value (17).
select parent_id, max(page_num)
from the_table
group by parent_id
Walter
"Ed Murphy" <emur...@socal.rr.com> wrote in message
news:46daf1aa$0$6385$4c36...@roadrunner.com...