The population and sample standard errors can be computed with the
appropriate following array formula (commit with ctrl+shift+Enter instead of
Enter):
=10^STDEVP(LOG(1+G2:G100)) - 1
=10^STDEV(LOG(1+G2:G100)) - 1
where G2:G100 are the growth rates Y1/Y2 - 1, Y2/Y3 -1, etc to Y99/Y100 - 1,
where Yn is the data for time "n".
By the way, the geometric mean can be computed with the following array
formula:
=10^AVERAGE(LOG(1+G2:G100)) - 1
That will work in situations where GEOMEAN does not.
Do you need to know how to compute the geometric standard error of the mean?
I wrote:
> where G2:G100 are the growth rates Y1/Y2 - 1, Y2/Y3 -1, etc
> to Y99/Y100 - 1, where Yn is the data for time "n".
That's okay if the data is sorted is descending time order. But I wrote "Yn
... for time n", meaning time 1, 2, etc. Normally that implies ascending
time order. In that case, the growth rates are typically Y2/Y1 - 1,
Y3/Y2 -1, etc to Y100/Y99 -1.
----- original message -----
"JoeU2004" <joeu...@hotmail.com> wrote in message
news:%23CyWL3n...@TK2MSFTNGP05.phx.gbl...
You're welcome. But be careful with how you use these statistics to analyze
data. In short, I would suggest that you do your statistical analysis on
the log values, converting to the antilog only at the last step, if at all.
For example, if the geometric mean and std dev are u and s, you cannot say
that some data point Gn is z = (Gn - u)/s std devs from the mean.
Similarly, the standard error of the mean is not SE = s/SQRT(n). [1]
Moreover, if you are analyzing periodic changes of stock prices, note that
it is the logs of historical return rates that people say are normally
distributed, not the return rates themselves.
Endnotes:
[1] FYI, the population and sample geometric standard errors of the mean can
be computed with the appropriate following array formula (commit with
ctrl+shift+Enter instead of Enter):
=10^(STDEVP(LOG(1+G2:G100)) / SQRT(COUNT(G2:G100))) - 1
=10^(STDEV(LOG(1+G2:G100)) / SQRT(COUNT(G2:G100))) - 1
----- my previous posting (corrected) -----
"JoeU2004" <joeu...@hotmail.com> wrote in message
news:%23CyWL3n...@TK2MSFTNGP05.phx.gbl...
> "Sandman" <San...@discussions.microsoft.com> wrote:
>> Can the geometric standard deviation of a dataset be calculated using
>> Excel?
>> I found the function for the geometric mean but have not been able to
>> figure
>> out how to calculate the GSD.
>
> The population and sample standard errors can be computed with the
> appropriate following array formula (commit with ctrl+shift+Enter instead
> of
> Enter):
>
> =10^STDEVP(LOG(1+G2:G100)) - 1
>
> =10^STDEV(LOG(1+G2:G100)) - 1
>
> where G2:G100 are the growth rates Y2/Y1 - 1, Y3/Y2 -1, etc to Y100/Y99 -
So how to calculate standard deviation of geometric mean?
I answered that question in my first response in the thread to which you
posted this response. How could you miss it? You are using the MS
Discussion Groups web interface. Using that interface, I can see the entire
thread, started on July 21.
Anyway....
----- my previous response -----
"JoeU2004" <joeu...@hotmail.com> wrote in message
news:%23CyWL3n...@TK2MSFTNGP05.phx.gbl...
> "Sandman" <San...@discussions.microsoft.com> wrote:
>> Can the geometric standard deviation of a dataset be calculated using
>> Excel?
>> I found the function for the geometric mean but have not been able to
>> figure out how to calculate the GSD.
>
> The population and sample standard errors can be computed with the
> appropriate following array formula (commit with ctrl+shift+Enter instead
> of
> Enter):
>
> =10^STDEVP(LOG(1+G2:G100)) - 1
>
> =10^STDEV(LOG(1+G2:G100)) - 1
>
> where G2:G100 are the growth rates Y1/Y2 - 1, Y2/Y3 -1, etc to Y99/Y100 -
> 1,
> where Yn is the data for time "n".
>
> By the way, the geometric mean can be computed with the following array
> formula:
>
> =10^AVERAGE(LOG(1+G2:G100)) - 1
>
> That will work in situations where GEOMEAN does not.
>
> Do you need to know how to compute the geometric standard error of the
> mean?
----- original message -----
"NoKiE" <No...@discussions.microsoft.com> wrote in message
news:E7C5A31B-E69D-4582...@microsoft.com...