Calling function using repeater (vb vs. c#)
sck10
I am calling a function using vb and want to convert it to c#. When moving
from vb 1.1 to vb 2.0, I can use the following: text='<%#
AddBlankRowMenu(Eval("strMenuType")) %>' to call the function. I no longer
need to use "DataBinder.Eval(Container,"DataItem." in front of the DataItem.
However, when I tried to use the new syntax in c#, I got an error. However,
the older syntax works.
Am I missing something, or does c# require the longer syntax as shown below?
--
Thanks, sck10
vb: asp.net 1.1
<asp:Literal id="ltrNewLine" text='<%#
AddBlankRowMenu(DataBinder.Eval(Container,"DataItem.strMenuType")) %>'
runat="server" />
vb: asp.net 2.0
<asp:Literal id="ltrNewLine" text='<%# AddBlankRowMenu(Eval("strMenuType"))
%>' runat="server" />
c#: asp.net 2.0
<asp:Literal id="ltrNewLine" text='<%#
AddBlankRowMenu(DataBinder.Eval(Container,"DataItem.strMenuType")) %>'
runat="server" />
Steven Cheng[MSFT]
As for the databinding expression in ASPX template, they're dynamically
compiled at runtime, and the error you encountered is likely due to the
different compile option between VB.NET and C#. For VB.NET, it is using
latebinding that means wo do not need to convert the object to the actual
expected type and the runtime will use latebinding to evaluate and
determine the object type. However, C# will always enforce type checking
at compile time, if there is type mismatch in code, it will report error.
Thus, for your case, "DataBinder.Eval" or "Eval"(asp.net 2.0 specific)
will return an "Object" , however, our custom function( such as the
"AddBlankRowMenu" ) will expect a non-Object type parameter, this will
cause the C# compilter report error. What's the object type expected by
the "AddBlankRowMenu" function in your case? You can consider:
1. Explicitly case the object returned from the "Eval" to the expected
type of the "AddBlankRowMenu" function before pass it to the function.
2. Change the "AddBlankRowMenu"'s input parameter to "Object" type , and
perform the type convertion inside the function.
Please feel free to let me know if there works for you or if you meet any
further problem on this.
Sincerely,
Steven Cheng
Microsoft MSDN Online Support Lead
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