Regular Expression -Gmail ID

[suhail khan]

Dear All

how to write regular expression of Gmail id like suhai...@gmail.com
in this @gmail.com would remain the same
characters before @ is variable ie keep changing

appreciate any help

regards
suhail

[Deepak Kumar Mahapatro]

([\w|\d]+[\.]?){1,}[\w|\d]+[@][g][m][a][i][l][\.][c][o][m]

this will work better

On Sun, Apr 29, 2012 at 11:28 PM, Deepak Kumar Mahapatro <deepakkumar...@gmail.com> wrote:

([\w|\d]+[\.]?[\w|\d]+)+[@][g][m][a][i][l][\.][c][o][m]

suhail

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Regards,

Deepak

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Regards,

Deepak

[Deepak Kumar Mahapatro]

([\w|\d]+[\.]?[\w|\d]+)+[@][g][m][a][i][l][\.][c][o][m]

On Sun, Apr 29, 2012 at 7:45 PM, suhail khan <suhai...@gmail.com> wrote:

suhail

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Regards,

Deepak

[Santosh S]

Can u explain this :

([\w|\d]+[\.]?){1,}[\w|\d]+[@][g][m][a][i][l][\.][c][o][m]

[Anish Pillai]

Hi,

\w means alphanumeric characters(A-Z, a-z, 0-9) including underscore(_). Like an_12
\d means numbers 0 to 9. Like 10110

[\w|\d] means either \w or \d. Like an_12

[\w|\d]+ means 1 more more occurences of the character(s) before +. Ex - an_12an_12

[\.]? means 0 or 1 occurrence of the character preceding ?, which is dot(.) in this case.

[\w|\d]+[\.]? can mean ani_123.

{1,} means 1 more or occurence of preceding character.

([\w|\d]+[\.]?){1,} means 1 or more occurrence of ([\w|\d]+[\.]?) Example ani_123.ani_123.ani_123.

[\w|\d]+ means 1 more more occurences of the character(s) before +. Ex - kumar_112

([\w|\d]+[\.]?){1,}[\w|\d]+ can become ani_123.kumar_112

[@][g][m][a][i][l][\.][c][o][m] means "@gmail.com"


Combining everything we get ani_123....@gmail.com


For more regular expression operators, check the below link.

http://www.automationrepository.com/2011/08/all-about-regular-expressions-in-qtp/

Cheers,
a n i s h

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ar

[Deepak Kumar Mahapatro]

gmail

On Mon, Apr 30, 2012 at 11:15 PM, Deepak Kumar Mahapatro <deepakkumar...@gmail.com> wrote:

sorry mail is not accepting _. so you can replace "\w" with "A-Z|a-z" 

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Regards,

Deepak

[Deepak Kumar Mahapatro]

sorry mail is not accepting _. so you can replace "\w" with "A-Z|a-z" 

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Regards,

Deepak