Thanks guys very useful information. I did not realize what was
happening with the output cell size because arcmap used the default
value of the input raster which I assumed it was okay.
Regardless now the model is working and makes it very easy to prepare
the data. But now I am running into another problem.
I get the message "outside of bounding box"
I have projected all my worldclim data in WGS 84 utm 35s. I have
checked the rows and columns of my ASCII files and they match. The
only thing that puzzles me is that when I open one of the ASCII files
in arcmap and also my sample points they do not match. But if I open
them separately they are in the right spot. Obviously my samples
coordinates are in decimals. Can someone please help, I am rather
confused. I was under the impression that it was preferable to project
the environmental data before using it as an input in maxent.
Thanks again for the help
On Mar 14, 6:02 pm, John B <
j.baumgart...@pgrad.unimelb.edu.au> wrote:
> I should add, though, that interpretation of unprojected output grids (i.e.
> Maxent's output) requires the same consideration of varying cell area.
>
>
>
> On Thursday, 15 March 2012 09:58:55 UTC+11, John B wrote:
>
> > It seems Marwa has beaten me to it, but here goes anyways...
> > *
>
> > 1.* Worldclim data units are degrees, so it seems you are working with 30
> > arc-second data. When projecting to UTM, your output grid will be in
> > meters. By specifying an output cell size of 0.0083333, you are in fact
> > instructing ArcGIS to give you a grid with cell size 8.3mm, so it's no
> > surprise it's crashing! When you set it to 1000, you are asking for an
> > output grid with 1km resolution.
>
> > *2.* I suspect that the Worldclim data is at least 16-bit signed, at
> > least for temperature grids which are expressed as temp*10 and therefore
> > the range of values allowed by 8-bit signed (i.e. -128 to 127) would be
> > insufficient. That said, I'm not sure why you're losing bit-depth. I'd
> > perform each step of your model in turn, manually, and inspect the outputs
> > to find out where this reduction in bit-depth is occurring.
>
> > *3.* Prepare yourself for a long-winded answer: Degrees of longitude
> > shrink from about 100km wide at the equator, to infinitely narrow (i.e. a
> > point) at the poles. However, cells in a lat/lon grid are all depicted as
> > equal size, so the area they represent must differ from north to south.
> > Because of this variation in cell size across your input grid, you can't
> > create an output grid that has *exactly* the same cell size. You could
> > make your cells have more-or-less exactly the same height as your input
> > grid, i.e. 0.0083333 degrees. Assuming the datum that you've used (WGS 84),
> > one degree of latitude (height) is 111319 m, so you would specify an output
> > cell size of 111319 * 0.0083333 = 928 m. Cell width will be now also be 928
> > m, which is slightly different to that of your input grid, depending on
> > location (cell width of the input grid would vary from ~928 m at the
> > equator to cos(*x*) * 928 m at latitude *x* (e.g. ~914 m at 10 degrees
> > latitude). As you can see, the difference is pretty trivial. For
> > simplicity, people would typically just project to a 1 km grid if using 30"
> > input data.
>
> > *On another note:* Usually we project a grid to more accurately represent
> > some aspect (e.g. angles, area, etc.) of the sphere. Projecting to UTM
> > preserves shape and direction, but distorts area and distance. We can use
> > Tissot's indicatrix as a simple tool to visualise the distortion across a
> > map. This involves drawing circles of consistent size at the center of each
> > cell prior to projection, and examining the shape/area of those circles
> > after projection. Here's one<
http://en.wikipedia.org/wiki/Scale_(map)#Mercator_projection>for the Mercator (90-degree rotation of the Transverse Mercator that you