Radical Equations

[noobcake93]

I know that this is very simple, but for some reason I keep getting
the wrong answer.

Y= √y+12

y +12 is all under the radical sign.

Thanks

[prate...@gmail.com]

Y=4
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[David Beckwith]

Square both sides so that you get:

y^2 = y + 12
=> y^2 - y - 12 = 0
=> (y - 4) * (y + 3) = 0

So the roots are 4 and -3. Not sure if -3 is a valid answer or not though.

[prate...@gmail.com]

-3 is not allowed as y>0