I then decided that even though I want to randomize whenever a new level is begun, I want each level to be the same every time.. In other words, the positions of the things on level 1 will always be the same, every time you start the game, and so on for all the other levels.
However, here's the problem:I understand that when you give the Random object a seed, it uses that seed to generate its list of numbers, which is obviously why all my r.Next()s are the same no matter how many times I re-open the program. BUT, it seems I have to COMPLETELY restart the entire program in order to reset it and get back to the first item in the list again...
Before, I was doing r = new Random(mySeed)upon death, and for some reason this didn't work.. But I instead moved that bit of code to be called when you click on New Game on the main menu, and now it works!?
I even added a breakpoint before and the code was definitely getting executed.. So then I did the whole, step through every single line, type debugging...Turned out there was a point in between then and the next time I start the game again when I was doing an r.Next() so that messed the whole sequence up!
When a processor-controlled device must be guaranteed to operate, designers often choose to reset the processor periodically rather than rely on a watchdog circuit. In low-power systems the periodic reset generator can consume a large part of the system current budget or may not be guaranteed to operate at low voltages.
This application note describes a low-power reset generator that generates a low going reset pulse of 100S duration once per second, consumes less than 1A and will operate from 1.8V to 5V with only slight variation of the output period.
The circuit is an adaptation of a normal relaxation oscillator with a differentiator and diode clamp on the output to generate the 100S low going pulse. The pulse width can be adjusted by varying CP or RP and the polarity changed by repositioning D1. The period can be adjusted by varying R1 or C1.
The 350nA supply current, 1.8V-5.5V supply voltage range and SOT23 package make the MAX919 ideal for this application. Measurements for the complete circuit give operating currents of less than 1A at 25C, which would allow the circuit to operate from a single AA lithium cell for 250 years!
With careful component choice this circuit is able to generate periods from mS to minutes. To ensure good temperature stability R1 and RP should be metal film and C1 and CP should be NP0 type capacitors. Assuming a CMOS type input, high impedance and with a logic threshold of 30% of the supply rail, then the following formulas can be used to adjust the output pulse width and period:
david ecpa - 10/29/2012 11:41 Bought a new JD generator to cope with Sandy. It don't work, makes no electric. Manual says to hit the reset button. That is obviously broken. Can I get around this switch some how to make it work? There are no parts available as they come out of New Jersey. Any help appreciated. It is a 2600 amp with two outlets.
I don't know if this will help, but it might be worth a try. We had some power outages some years ago, and standby generators would not work. Several people said they plugged in a drill or electric fan into the generator without it being started, that is, not running. It was told to me that sometimes the magnetic field needs to be excited by plugging in a device and spinning it, then starting the generator to see if it works then. There may be new technology in newer generators that makes this advice no longer valid, but it sure won't cost anything to try.
First one point: in general you probably don't want to use "range" in a generator expression because that actually builds the list, and avoiding list construction is one of the reasons people use generators and iterators in the first place. You often have to have a pretty sizable array to notice the difference, I admit:
Note that there are int construction overheads the first time, and for small range size (for some definition of small) the difference won't matter -- range might even be faster -- but it's still going through the loop, so it'll break for really big sizes even if you only ever look at a few values. Try w=10**9 and prepare to wait..
As for your real question, I don't know of a good way to clone a generator expression using the standard tools. (A ".restart()" method wouldn't make any sense in many cases, which is one of the reasons it's not part of the protocol.) You can use itertools.tee to make multiple cached copies of the output, but since it's caching the values to do the trick you could have memory problems or accuracy problems if the function is nondeterministic.
The basic answer seems to be that generators can't be reset. Instead, you could re-run the code which creates the generator to make a fresh copy of it, or you could store the outputs of the generator in a list so that you can reuse them. If neither of these will work, you could perhaps modify how the generator is built so that re-creating it does not take too long (for example, do computationally intense parts first, store the output, and use that to create the generator).
I have been told there must be a way to reset a generator without re-declaring it, and i have to find it :SI have been for long time on the doc searching, but I either found the way to reset it, or that there is no way to do that.
"I have been told there must be a way to reset a generator without re-declaring it[.]" Perhaps you should ask whoever told you there must be a way what exactly that way is, and if they can't tell you, you might wonder how they're so sure. :^)
I'm not sure what you'll accept as evidence. You could read up on the generator protocol: , or (maybe simpler) the functional programming tutorial ( ): "Note that you can only go forward in an iterator; theres no way to get the previous element, reset the iterator, or make a copy of it. Iterator objects can optionally provide these additional capabilities, but the iterator protocol only specifies the next() method." You can trivially write something you *can* reset, if for some reason you like g.reset() more than g=gen(), but from a standard genexp it won't work. [Actually I can think of some low-level tricks which could probably pull off a reset but they're a terrible idea.]
The ESP8266 supports a "deep sleep" function, in which it consumes very little power. However, the only way to wake it up is to reset it (by pulling the reset pin low - the device will restart as soon as the pin goes high again).
So I am trying to use an external event (let's say a normally-open switch) to wake up the device. However, there is a snag - the device should wake up immediately after the switch is closed, even though the switch might remain closed for many seconds or minutes afterwards. So I need a circuit that will generate a reset pulse (low, then high after several milliseconds) whenever the switch is closed.
But of course real life does not fit the simulation... I am using a Wemos D1 Mini development board - which adds a whole new level of complexity, including a pull-up resistor on RST and a capacitor between RST and ground. So, of course, this simple circuit no longer works :(
Looks like you could easily go to 10nF and 10M resistors, and even less on the capacitance but take care of the MOSFET input capacitance if you try to go very low or try to substitute a different type of MOSFET (most of which will have much higher gate charge).
Also from the comments I see a false issue with the "voltage doubler", the voltage on Reset pin will be divided between R1 and R3 to 1/10 order which means Reset pin can go at most 0.36V over V1 with a 36uA maximum current which is allowed.
The drawback for multiple switches is that you will have to wait for all SW to be steady opened for a time to ensure that you don't loose any data but if they stay mostly opened this simple solution could work well.
The capacitor is charged to VCC until you bypass it using the switch. Once the switch is used, it will discharge the capacitor completely. If you want the discharge to be slower, you can put a resistor in series with the switch.
Regarding question 1: the only current that will be wasted is the leakage current that will pass through the reset port and through the capacitor (leakage current). Those are unavoidable unfortunately.
Regarding question 2: You can add many other switches in parallel with the first one. Each switch will be able to reset the ESP8266. However, if you want to route each switch to a GPIO, you will need a different kind of switch and configuration:
R2 and R3 maintain a pull up status to your GPIO to ensure that it can differentiate correctly between a 0 and a 1. You could reverse VCC and ground on that sub circuit if you want the opposite (now that I think about it, it might even be better to pull down and prevent leakage current!) You could create a similar logic using a double throw switch depending on what you have readily in your hand.
The RESET signal is connected to the node where the Voltimetes is connected (between the 100 ohms resistor and the diode. The 3,3k resistor must be removed, I put it to simulate the internal impedance of the RESET pin. Hope it works for you
I was messing though the menus of the AH-64D while in flight; apparently, I disabled generator 1 and 2: which cut all electrical power to all electronics. To my surprise; the chopper kept flying; trimming was still possible; and I managed to land it. But it was impossible to re-enable those generators as they are activated through a menu, which after disabling the generators; is no longer reachable. Is there a way to re-strat them through a button? Or is it some kind of Doom-function?
As tech_op2000 mentioned, the reset switch in the pilot cockpit is used to turn the generators back on. As you have observed, you lose MPDs when you lose generator power, therefore this physical switch is required.
Reset Breaker for Power Tech Generators. Reset breakers are located on the control box of your generator along with the main on/off switch and main breakers. Reset breakers protect the circuit from surges. When your generator experiences a surge, these breakers need to be pushed in to be reset. Overtime, reset breakers need be replaced if they become weak.
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