Link-Grammar Wordlist output to a (txt) file.. possible future feature

[Dennis Grubb]

Is it possible to output the (or a) dictionary wordlist to a text file, probably just the word and its type, with comma separators so it can be imported into a spreadsheet.

I note that it can be sent to the console screen with the "!!*" command, so redirection and filtering should not be too difficult.

Easier then to note omissions, and more.

I guess this functionality should sit in dict-api

Dennis

[ami...@gmail.com]

Hi Dennis,

Instead of the !!* command at the "linkparser>" prompt, you can use the -!* argument of link-parser.

Here is how to do it on Windows:

 

First produce a word list (one per line) by the following cmd console command:

(for /f  %a in ('link-parser -!* ^< nul ^| findstr /c:"disjuncts <"') do @echo %a) > wordlist.out

The words are output as e.g. test.n and if you would like to separate the "type" (called the word "subscript") with a comma instead of dot then you will need to process this list further, possibly by using PowerShell regex. (You need to replace the last dot with a comma, not just any dot because some words are abbreviations that include dots.)

Amir

[Dennis Grubb]

Thanks Amir,

I will try your solution.

Where is the documentation regarding console command arguments for link-parser ?

Would it be particularly difficult to add into dict-api ?

Dennis

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[ami...@gmail.com]

On Monday, 13 December 2021 at 09:00:06 UTC+2 dennis....@gmail.com wrote:

Thanks Amir,

I will try your solution.

Where is the documentation regarding console command arguments for link-parser ?

It is in the file "man/link-parser.1".  However, it is not so readable on Windows.

You can read it on the Web by googling:

man link-parser 5.9.0

(The last version of this file is from LG version 5.9.0.)

You will find out that almost all the arguments are in the form -X when X is a link-parser variable or "!".

Would it be particularly difficult to add into dict-api ?

There is not much point in doing so since it can easily be done by manipulating the output of -!* .

However, you can add a function similar to print_dictionary_data() to the API, or even easier, change it to print the dictionary words in any format you desire when link-parser is invoked with e.g. -verbosity=105 (so no need to add anything to the list of API functions).

Dennis

Amir

[Dennis Grubb]

Thanks Amir,

great solution for me.. and I now understand the -!* argument

Much appreciated help.

[ami...@gmail.com]

Hi Dennis,

In case you have not seen it yet, the ! command also has some esoteric options that you may find interesting.

You can see its documentation using the !help command of link-parser:

linkparser> !help !

(The help file is data/en/command-help-en.txt so you can also read it directly.)

Amir

[Dennis Grubb]

Thanks Amir, I will take a look. 

Dennis

Sent from my iPhone

On 27 Dec 2021, at 22:08, ami...@gmail.com <ami...@gmail.com> wrote:

Hi Dennis,

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[ami...@gmail.com]

In a private mail, Dennis pointed out that the command I provided below doesn't list many words.

And indeed the filter I applied in it is too strict.

Here is the fixed command (for clarity I added a blank between " and ' , and also note the two blanks before "disjunct"):

(for /f  %a in ('link-parser -!* ^< nul ^| findstr/r /c:"[0-9]  disjunct" ') do @echo %a) > wordlist.out

Amir