Extract Json values as Map with lift-json

[Gregg Carrier]

The documentation for lift-json suggests that I should be able to call 
'values' to get my current JObject structure as a vanilla Scala Map. 
This approach is not working for me, as the return type of 'values' is 


json.Values rather than a Map as the examples show. What am I doing 
wrong?


scala> val json = parse("""{"k1":"v1","k2":"v2"}""")         


json: net.liftweb.json.package.JValue = JObject(List(JField(k1,JString(v1)), JField(k2,JString(v2))))



scala> json.values                                  
res4: json.Values = Map((k1,v1), (k2,v2))



scala> res4.get("k1")                                        


<console>:18: error: value get is not a member of json.Values


   res4.get("k1")

[David Pollak]

Looks like a REPL problem.  Try compiling the same code.
 

   res4.get("k1")

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[Joni Freeman]

Hi,

'parse' function returns JValue, not JObject. You can cast it to JObject
if you are sure that the JSON you are parsing is a JSON object. The
static type of 'values' function is then known to be a Map.

scala> val json = parse("""{"k1":"v1","k2":"v2"}""")
json: net.liftweb.json.package.JValue =
JObject(List(JField(k1,JString(v1)), JField(k2,JString(v2))))

scala> json.asInstanceOf[JObject].values
res2: scala.collection.immutable.Map[String,Any] = Map((k1,v1), (k2,v2))

Cheers Joni

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