zprime = 0.5 * log((1+rg) / (1-rg))
ci = zprime ± 1.96*se
ci = ((exp(2*ci) - 1) / (exp(2*ci) + 1))
If using Fisher's z transformation, I'm also not completely sure how to transform the standard error and/ or whether this has already been transformed.
I couldn't find a similar question in the google group but my apologies if I missed it somewhere and this is redundant.
Thanks in advance for the support and response!
Best wishes,
Nils