Hello.
I am modelling lightweight steel framed (LSF)
partition walls (THERM models available here: https://www.dropbox.com/s/gmaviienxzhp4rg/THERM_models.zip?dl=0 ) and simulated several surface thermal
resistances (Rs), i.e, the reciprocal
of the film coefficient (h).
The inner surface thermal resistance (Rsi) was fixed to 0.13 (hi=7.69) for a 20ºC indoor environment temperature, while the external surface thermal resistance (Rse) was changed from 0.00 up to 0.20 (with intermediate values: 0.04; 0.08; 0.13; 0.16), for a constant “exterior” (or unconditioned interior) environment temperature of 10ºC.
Very surprisingly, I found that the conductive (surface-to-surface) thermal resistance (R-value) changed significantly from 1.52 m2.K/W up to 1.65 (+8%), as illustrated in the following chart:
The question is:
Does anyone have an explanation for this unexpected significant conductive R-value variation for the same wall by changing only the external surface thermal resistance (Rse)??
Thanks in advance.
BR, Paulo
Dear Roro,
thanks for your wise explanations.
I also simulated in ANSYS using a 3D model and the conductive R-value also changed with different surface thermal resistances.
Making use of the THERM results i also computed the internal surface thermal resistance (Rsi) and compared with the input Rsi values:
Similar graph for external surface thermal resistance (Rse) :
Similar for Rsi + Rse:
As you can see, the computed surface thermal resistance is (in general) lower than the input values.
Shouldn't these values be the same or very similar??
If you need to characterize the studied LSF wall, what conductive R-value would you choose ??
THANKS in advance.
BR
Dear roro,
thanks for your reply.
Regarding your queries:
1. I am not comparing THERM and ANSYS surface thermal resistances. All values presented here were obtained or computed by THERM software.
2. “what you call your input surface resistance is the 1/h value , where h is what you provide in THERM ?”
Yes, You are right.
3. “it is still not clear to me how you calculated your so-called computed surface resistance.”
Sorry for the misunderstanding, but I will try to better clarify this point.
The computed surface resistances were calculated making use of the input environment temperatures (Ti=20ºC and Te=10ºC in these partition wall simulations), the average computed surface temperatures (Tsi and Tse) and the computed heat flux (q in W/m2) across the wall. The formula was Rs = (T – Ts) / q
Thanks. BR,
Paulo
Dear Charlie,
thanks for your reply.
Yes, I agree with you and also performed a similar 1D analysis (assuming homogeneous wall layers), where the results are illustrated in this graph:
and found an almost constant conductive (or surface-to-surface) R-value if computed with the theoretical INPUTTED surface thermal resistances (Rcond1 in the plot).
However, if you calculate the conductive thermal resistance making use of the COMPUTED heat flux (q) and COMPUTED surface temps (Tsi and Tse):
Rcond2 = (Tsi - Tse) / q
the obtained values are not so similar (red line in the graphic).
I believe that this small millesimal differences could be related with rounding errors, for which I have no worries.
However, I am concerned about the MAJOR differences found in a 2D LSF partition wall models for similar calculations, but this time to obtain the computed SURFACE thermal resistances, as shown in a previous post:
As you can see here, the theoretical INPUT inner surface thermal resistance is constant (Rsi = 0.13). However, the COMPUTED Rsi significantly increase with the increase of the external surface resistance (Rse), changing from 0.116 up to 0.138.
Shouldn’t the COMPUTED Rsi values (in red) be equal (or very similar) to the INPUTTED inner surface thermal resistance (Rsi in black) ??
Just in case you missed a previous post to Roro Sell, the COMPUTED surface resistances were calculated making use of the input environment temperatures (Ti=20ºC and Te=10ºC in these partition wall simulations), the average computed surface temperatures (Tsi and Tse) and the computed heat flux (q in W/m2) across the wall. The formula was:
Rs = (T – Ts) / q
Thanks. BR,
Paulo
Dear Yalin,
thanks for your reply.
Yes, I agree with you regarding the big conductivity heterogeneity relevance in the thermal resistance calculations for these type of LSF walls.
I also know very well the figure you shared:
which was obtained from this journal paper:
https://www.mdpi.com/1996-1073/13/4/840
However, when you define as input boundary conditions some SURFACE thermal resistances (internal: Rsi and external: Rse) equal to a specified values and after the computations you obtained different output values, to me it is strange and hard to understand!!
See for instance this example, for an input Rsi = 0.13:
where the output computed Rsi differences ranges from -11% (for Rse = 0.0) up to +6.4% (for Rse = 0.20)!!
Do you have a reasonable explanation for this discrepancies??
Thanks in advance.
BR, Paulo