Surprises are always important and worth tracking down. Since the factor variance is a free parameter, you must have scaled that factor by fixing a loading to 1. This approach certainly could obscure the fact that a factor and its indicators are only weakly linked. Check the R2’s for the indicators of that factor. I think you will find that they are low—and that is a reason that people have used to doubt the value of a model.
The relation between indicator X and factor F can be expressed as:
X = loading * F + e
If loading is fixed to 1, this becomes:
X = F + e
Implying the variance equation:
Var(X) = var(F) + var(e)
Or:
Var(F) = var(X) – var(e)
So if var(F) is small, then var(X) and var(e) must be about the same size. In other words, very little of var(X) is being accounted for by the factor. So check the R2’s for the indicators of the factor.
“Significance” is affected by both the size of the parameter and sample size. Low sample size tends estimates toward nonsignificance and also reduces the power of the chi-square test. If your estimates lack significance, maybe this is a caution that the chi-square isn’t testing very much.
--Ed Rigdon
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Philipp—
I can’t speak for anyone else. For myself, “statistical significance” is overvalued. If you want to read more, I recommend the works of Gerd Gigerenzer. For myself, knowing the link between variance of indicator, residual variance and variance of factor, I would think that something was wrong if one of my factors had a surprisingly small variance, whether it was “significant” or not.
In a published context, researchers might be more likely to talk about the low indicator R2s than about the variance of the factor. Deleting a single item can change the performance of the factor model, possibly eliminating the “low variance” condition. A researcher might prefer to delete single items in the hope of salvaging the rest, rather than discard the factor and all of its indicators.
--Ed Rigdon
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