On Oct 17, 7:43 am, XeTaL <
kooo...@gmail.com> wrote:
> Thanks a lot Werner. This may be acceptable, I guess, but I need the
> whole block moved to the far left. I'd appreciate it if you could take
> a look at the file section of the forum where I posted another file
> named eqnarray+lefteqn2.pdf showing the position I need for the block.
> Hope that can be done. If not, I should probably live with what you
> showed me.
Of course it's possible:
\documentclass{article}
\usepackage{lipsum,amsmath}
\setlength{\parindent}{0mm}
\begin{document}
\lipsum[1-2]
$ \begin{array}{@{\hspace{0mm}}r@{\;}l@{\hspace{0mm}}}
\tau & = \displaystyle \beta\left(t-\frac{v^2}{c^2}t\right)=
\beta t\left(1-\frac{v^2}{c^2}\right) \\[5\jot]
& = \displaystyle t\frac{\sqrt{1-\frac{v^2}{c^2}}\sqrt{1-
\frac{v^2}{c^2}}}{\sqrt{1-\frac{v^2}{c^2}}} \\[7\jot]
& = \displaystyle t\sqrt{1-\frac{v^2}{c^2}}
\end{array}
$ \hfill \phantom{.}
\lipsum[3-4]
\end{document}
I've added the lipsum package just to show perspective in terms of the
page dimensions, and also removed the regular paragraph indentation.
Would this work for you?
Werner