Representação de um somatório
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Heitor Galvão
Apr 13, 2016, 4:27:19 PM4/13/16
to Latex-br
Boa tarde preciso representar a seguinte expressão no latex:
começei ela assim:
\begin{eqnarray}
P_{e}\leq \frac{1}{2}\cdot \sum_{i=T_{h}}^{K-1} (q)^{i} (1-q)^{k-1-i}
\end{eqnarray}
Alguém possui alguma sugestão de como encaixar aquele matrix 2X1 dentro desse somatorio?
Obrigado desde já.
Youssef Cherem
Apr 13, 2016, 4:39:57 PM4/13/16
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\begin{align}
P_{e}\leq \frac{1}{2}\cdot \sum_{i=T_{h}}^{K-1}\begin{pmatrix}K - 1\\i\end{pmatrix}
(q)^{i} (1-q)^{k-1-i}
\end{align}
P_{e}\leq \frac{1}{2}\cdot \sum_{i=T_{h}}^{K-1}\begin{pmatrix}K - 1\\i\end{pmatrix}
(q)^{i} (1-q)^{k-1-i}
\end{align}
Youssef Cherem
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Heitor Galvão
Apr 13, 2016, 5:12:26 PM4/13/16
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aqui não compila
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"Ganhar de ponta a ponta."
Ayrton Senna
Heitor Galvão
Apr 13, 2016, 6:26:08 PM4/13/16
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Boa noite como voce pode ver demorou um pouco ler e testar soluções mais segue(resolvido):
\begin{eqnarray}
P_{e}\leq \frac{1}{2}\cdot \sum_{i=T_{h}}^{K-1}\left(\begin{array}{c}K-1\\ i\end{array}\right)q^{i}(1-q)^{k-1-i}
\end{eqnarray}
gera: \begin{eqnarray}
P_{e}\leq \frac{1}{2}\cdot \sum_{i=T_{h}}^{K-1}\left(\begin{array}{c}K-1\\ i\end{array}\right)q^{i}(1-q)^{k-1-i}
\end{eqnarray}
Youssef Cherem
Apr 13, 2016, 7:11:08 PM4/13/16
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está usando amsmath?
Youssef Cherem
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Youssef Cherem
Apr 13, 2016, 7:12:17 PM4/13/16
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o que eu fiz foi que eu gerei um resultado idêntico ao seu, com menos trabalho...
Youssef Cherem
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Heitor Galvão
Apr 13, 2016, 7:15:15 PM4/13/16
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isso amsmath
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Youssef Cherem
Apr 13, 2016, 7:20:57 PM4/13/16
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Então:
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{align}
P_{e}\leq \frac{1}{2}\cdot \sum_{i=T_{h}}^{K-1}\begin{pmatrix}K - 1\\i\end{pmatrix}
(q)^{i} (1-q)^{k-1-i}
\end{align}
\end{document}
Youssef Cherem
________________
!المسيح قام! حقاً قام
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Heitor Galvão
Apr 13, 2016, 7:31:43 PM4/13/16
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hm...compilou agora... =)
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Tássio Naia
Apr 14, 2016, 3:43:47 AM4/14/16
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Olá,
Sugiro \binom{n}{k} para binomiais.
Até,
Tássio
Heitor Galvão
Apr 14, 2016, 7:56:39 AM4/14/16
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ok.
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