Hello. Now I connect webrtc from clients to httpgetendpoint, get address and pass it to my app on server. But Rtp stream is more suitable for it. How should I build pipeline(node is) and more important how can I get full rtp address of stream?
--
You received this message because you are subscribed to the Google Groups "kurento" group.
To unsubscribe from this group and stop receiving emails from it, send an email to kurento+u...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.
pipeline.create('WebRtcEndpoint', function(error, webRtc) { pipeline.create('RtpEndpoint', function(error, Rtp){ webRtc.connect(Rtp, function(error){ console.log(Rtp); webRtc.processOffer(sdpOffer, function(error, sdpAnswer) { if (error) { pipeline.release(); return callback(error); } console.log(sdpAnswer); pipelines[sessionId] = pipeline; return callback(null, sdpAnswer); }); });});v=0
o=- 3719649243251346151 0 IN IP4 0.0.0.0
s=TestSession
c=IN IP4 0.0.0.0
t=0 0
a=group:BUNDLE audio video
m=audio 47611 RTP/SAVPF 0
c=IN IP4 192.168.51.208
a=rtpmap:0 PCMU/8000
a=sendrecv
a=rtcp:47611 IN IP4 192.168.51.208
a=ice-ufrag:rGbt
a=ice-pwd:o8SxDSLHlLx3JRjIDZuoAf
a=fingerprint:sha-256 91:1F:93:1B:24:18:78:65:4F:06:FB:01:4E:05:8D:AB:C1:65:38:13:13:97:EA:4B:77:A1:1F:27:94:F0:A0:AC
a=rtcp-mux
a=candidate:1 1 UDP 2013266431 192.168.51.208 47611 typ host
a=ssrc:3774244161 cname:user2339755957@host-75a473c
m=video 47611 RTP/SAVPF 100
c=IN IP4 192.168.51.208
a=rtpmap:100 VP8/90000
a=sendrecv
a=rtcp-fb:100 ccm fir
a=rtcp-fb:100 nack
a=rtcp-fb:100 nack pli
a=rtcp:47611 IN IP4 192.168.51.208
a=ice-ufrag:rGbt
a=ice-pwd:o8SxDSLHlLx3JRjIDZuoAf
a=fingerprint:sha-256 91:1F:93:1B:24:18:78:65:4F:06:FB:01:4E:05:8D:AB:C1:65:38:13:13:97:EA:4B:77:A1:1F:27:94:F0:A0:AC
a=rtcp-mux
a=candidate:1 1 UDP 2013266431 192.168.51.208 47611 typ host
a=ssrc:1872238046 cname:user2339755957@host-75a473c
avprobe rtp://192.168.51.208:47611