Hello, How do I set the number of chars at TextInput, I want to limit 10 characters.

[노재화]

Hello dears.

I want to make Textinput which can typo only '10 characters'.

In a nutshell, limit length of TextInput as 10.

I retrieve the documents at TextInput section. but, I couldn't find about length of words at Textinput.

How can I do?

Thanks.

[Elliot Garbus]

Look at the filtering examples: https://kivy.org/doc/stable/api-kivy.uix.textinput.html?highlight=text%20input#module-kivy.uix.textinput

And do the filtering based on length.

 

I did a filter that does not allow characters that are not allowed in a filename, and puts up a warning message if the name is already in the library the user created:

class ValidFilenameInput(TextInput):
    invalid_set = r"/\*:|'.?" + '"<>'

    def insert_text(self, substring, from_undo=False):
        patch_name = [c for c in substring if c not in self.invalid_set]
        s = ''.join(patch_name)
        return super().insert_text(s, from_undo=from_undo)

 

and create a widget in kivy

ValidFilenameInput:
    id: patch_name
    multiline: False
    hint_text: 'Name'
    size_hint: (None,None)
    size: (400,30)
    on_text: input_warning.text = 'Name is Already in Library, Change the Name' if self.text in app.mylib else ''

 

You could do something similar, but stop returning chars after the first 10 are input.

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[노재화]

Dear Elliot Garbus.

Thanks. Your reply is helping to me a lot.

I made the code from you had gave me.

below is that.

class ValidFilenameInput(TextInput):

    

    count = 0

    def insert_text(self, substring, from_undo=False):

        patch_name = [c for c in substring if self.count < 10]

        s = "".join(patch_name)

        if self.count < 10:

            self.count += 1

        return super().insert_text(s, from_undo=from_undo)

Thanks to you repeatedly.

Have a good day!

2019년 2월 24일 (일) 오전 1:50, Elliot Garbus <elli...@cox.net>님이 작성:

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[Elliot Garbus]

I'm glad to hear it helped.

You could simplify your code, something like this should work.  (I have not tested this).  You do not need to examine every character.

def insert_text(self, substring, from_undo=False)
    if len(substring) < 10 :  #  if the length of the substring is less than 10, return the substring
            s = substring
    else:
            s = substring[0:10]  # is the substring length is 10 or greater, only return the first 10 characters
    return super().insert_text(s, from_undo=from_undo)

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[노재화]

Dear Elliot Garbus.

Oh, your suggestion is very charm.

But, It doesn't work when I use your new code.

the substring returns one character not full contents of TextInput.

Anyway, you are so kind.

Take care.

2019년 2월 25일 (월) 오전 11:44, Elliot Garbus <elli...@cox.net>님이 작성:

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[jw]

I found another way to do this:

1. Create a class for the textinput

2. Create a handle in the on_text event that sets readonly to True if the len == 10

3. Create a method in the textinput class that you created called keyboard_on_key_up and check if the readonly is True and the key is backspace then set readonly to False and do_backspace()

like this:

(in kv file)

on_text:

    self.readonly = True if len(self.text.strip()) == 10 else False

(in python file)

class LimitInput(TextInput):
    def keyboard_on_key_up(self, keycode, text):
        if self.readonly and text[1] == "backspace":
            self.readonly = False
            self.do_backspace()

hope this helps!

-Jaivin

[노재화]

Dear  Jaivin.

Oh, your code is simple and great.

I test it. and It works!

Thanks and Have a good day!

2019년 2월 26일 (화) 오후 12:31, jw <74i...@gmail.com>님이 작성:

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[Jaivin Wylde]

No problem!

One thing I forgot to mention is that this will only work on desktop, if you want it to work on mobile you would do something like this:

Create this method in the text input (instead of keyboard_on_key_up):

def insert_text(self, substring, from_undo=False):
    if not self.filled:
        return super(IdeaInput, self).insert_text(substring, from_undo=from_undo)

Create this in kv under the text input:

on_text:

    self.filled = True if len(self.text.strip()) >= 10 else False

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[노재화]

Dear  Jaivin. 

Oh, you gave to me another advice about the mobile!

I haven't made the mobile app now, but Thanks your offer when I make the mobile app.

Best regards.

2019년 2월 28일 (목) 오전 7:24, Jaivin Wylde <74i...@gmail.com>님이 작성:

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