How to open a document with the default application

[sebastián lópez]

Hi

I would like to know how to open a document with the default application under Android by given the path.

Thanks!

[ZenCODE]

import webbrowser

webbrowser.open("path/to/file")

That should do it?

[sebastián lópez]

Hi, It doesn't work

So I'm trying with this

PythonActivity = autoclass('org.renpy.android.PythonActivity')
Intent = autoclass('android.content.Intent')
String = autoclass('java.lang.String') 
Uri = autoclass('android.net.Uri')
# filename : is the file name full path

fileNameJava = cast('java.lang.CharSequence', String(filename))
file = cast('java.io.File', fileNameJava)
target = Intent()

target.SetAction(Intent.ACTION_VIEW)

target.setDataAndType(Uri.fromFile(file),"application/pdf")

target.setFlags(Intent.FLAG_ACTIVITY_NO_HISTORY)

intent = Intent.createChooser(target, 'Abrir el archivo')

currentActivity = cast('android.app.Activity', PythonActivity.mActivity)

currentActivity.startActivity(intent)

But it still doesn't work. I have tried using the Kivy Launcher but it fails

[sebastián lópez]

I have found two errors

target.SetAction --> target.setAction 

urifromfile = Uri.fromFile(file2view)  # unknown

[ZenCODE]

Why does it "not work"? What is the error? This works for us on all platforms (Sorry, got the function name wrong in the first post).

webbrowser.open_new(ad_item["/path/to/file.pdf")

[sebastián lópez]

I try again your approach and it doesn't work, but don´t crash.

In the other hand a fix the error and obtain this script

        PythonActivity = autoclass('org.renpy.android.PythonActivity')  #request the Kivy activity instance

        Intent = autoclass('android.content.Intent')

        String = autoclass('java.lang.String') 

        Uri = autoclass('android.net.Uri')

        fileNameJava = cast('java.lang.CharSequence', String(filename))

        File = autoclass('java.io.File')

        target = Intent()

        target.setAction(Intent.ACTION_VIEW)

        urifromfile = Uri.fromFile(File(filename))

        target.setData(urifromfile)#setDataAndType( urifromfile,"application/pdf")

        target.setFlags(Intent.FLAG_ACTIVITY_NO_HISTORY)

        #intent = Intent.createChooser(target, 'Abrir el archivo')

        currentActivity = cast('android.app.Activity', PythonActivity.mActivity)

        currentActivity.startActivity(target)

It' doesn't crash and shows me a dialog to select an app in order to open the file

but then shows me the file doesn't exists

This is the path since it was created:

filename = '/storage/emulated/0/kivy/tarjetas/reportes/201.pdf'

And It's also the file I'm trying to open

[ZenCODE]

Try making that

 'file://storage/emulated/0/kivy/tarjetas/reportes/201.pdf'

The problem with using PythonActivity is that it's Android only, and more complex for a simple task. Or perhaps you have another reason for preferring it?

[sebastián lópez]

Hi,

My target os are android and windows,

so on windows I've been using os.startfile, and in the other hand the previous code.

I fix the error by putting a popup message before. I think the error was related to the time the system takes to create the pdf file