how to get index of a widget which in present in boxlayout

[Degenerate Tech]

i have two widget wid1 and wid2  where wid1 already present in a boxlayout i want to replace wid1 by wid2 in same index so . widget position be same .

how to do ? for that i need index of that widget . how to read ? that

[Degenerate Tech]

solved by using python list indexing .

["foo", "bar", "baz"].index("bar")

[elli...@cox.net]

The children list of the boxlayout is a list.  You can use the list index() method and pass in the widget and it will return the appropriate index.

from kivy.app import App
from kivy.lang import Builder
from kivy.uix.button import Button

kv = """
BoxLayout:
    ScrollView:
        BoxLayout:
            id: box
            orientation: 'vertical'
            size_hint_y: None
            height: self.minimum_height
"""

class IndexButton(Button):
    def on_release(self):
        app = App.get_running_app()
        children = app.root.ids.box.children
        index = children.index(self)
        print(f'This button is at index: {index}')

class IndexWidgetDemo(App):
    def build(self):
        return Builder.load_string(kv)

    def on_start(self):
        box = self.root.ids.box
        for i in range(20):
            box.add_widget(IndexButton(text=str(i), size_hint_y=None, height=48))

IndexWidgetDemo().run()

You can also see the children list is the opposite order of insertion. 

---

From: kivy-...@googlegroups.com <kivy-...@googlegroups.com> on behalf of Degenerate Tech <sksah...@gmail.com>
Sent: Friday, April 19, 2024 6:12 AM
To: Kivy users support <kivy-...@googlegroups.com>
Subject: [kivy-users] how to get index of a widget which in present in boxlayout

 

i have two widget wid1 and wid2  where wid1 already present in a boxlayout i want to replace wid1 by wid2 in same index so . widget position be same .

how to do ? for that i need index of that widget . how to read ? that

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