How to calculate water pressure at different depths?

[MeYak]

The pressure of different depths is found by the equation rgh = P where r is
the density of the water, g is the acceleration of gravity and h is the depth
of the water. The density of seawater is about 1X10^3. This equation will work
for any fluids, but the problem is that the density of sea water is not a
constant throughout the depths of the ocean.

[Bob Henninger]

Can anyone give me the formula for calculating the water pressure in
the ocean at different depths. Thanks ahead.

[Gina]

In <34613bf7....@news.ptd.net> wiz...@postoffice.ptd.net (Bob

Henninger) writes:
>
>Can anyone give me the formula for calculating the water pressure in
>the ocean at different depths. Thanks ahead.

>>>I atmosphere of pressure at every 33ft of depth.

Surface=1 atm.
33 ft.= 2 atm
66ft. = 3 atm and so on...

[Dr Jamie Love]

In article <34613bf7....@news.ptd.net>,

wiz...@postoffice.ptd.net (Bob Henninger) wrote:
>Can anyone give me the formula for calculating the water pressure in
>the ocean at different depths. Thanks ahead.

Hi there Bob!

An easy rule of thumb is that each 10 meters puts an extra atmosphere on you.
That's only a rough approximation, but you may find it a quick way to keep
track of it (to about one significant figure).

Jamie/Merlin

Dr Jamie Love email ja...@enterprise.net
Creator of "Alchemy by Merlin, the best Chemistry course(s) on the Internet.
http://www.virtual-pc.com/mindweb/merlin/alchemy
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[Shawn Yasutake]

In article <346BE...@mhvx.net>, Lepore <lep...@mhvx.net> wrote:

> Pressure at depth h, in a fluid of density rho, where
> accleration of gravity is g, is P = rho g h. Just multiply
> them. Actually, you have to add atmospheric pressure to
> that, but that's the extra pressure due to depth in the
> fluid. Here's an example using SI units. You're in water,
> water density = 1000 kg/m^3, at depth 200 m, P = rho g h =
> (1000 kg/m^3)(9.8 m/s^2)(200 m) = 2.02E6 Pascals.
> Dividing by 1.013E5 to convert pressure to units of
> atmospheres, that would be 19.93 atm.
>
> --
>
> Mike Lepore
> lep...@mhvx.net
> you must delete the x when sending mail

actually, IIRC, the density of seawater is more like 1.035 g/cm^3 (1035
kg/m^3), due to the presence of the dissolved salts. Pure water has a
density of 1.00 g/cm^3 (1000 kg/m^3).