Getting output of jupyter_client execution

[saso...@colorado.edu]

Hi,

I am trying to use the Jupyter_client API to run some code on a kernel. I am able to execute the code, but am not able to view the execution output. 

So far, I have tried the following

import jupyter_client

a = jupyter_client.KernelManager()

a.kernel_name = "python3"

a.start_kernel()

p = a.client()

m = p.execute("print('Hello, World')")

I tried using p.get_shell_msg(m) as suggested by the documentation, but I just got a JSON object, which didn't have the output. Am I missing something here?

Thanks,

Saurabh

[Jan Schulz]

Hi,

knitpy used this infrastructure to run code, so this might help:
https://github.com/JanSchulz/knitpy/blob/master/knitpy/knitpy.py#L458

Best,

Jan
--
Jan Schulz
mail: ja...@gmx.net

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[saso...@colorado.edu]

Thanks for the reply Jan. I will look through the code and see how to get it working.

I have a general question. So if I try to run code using jupyter_client, am I running against a running instance of Jupyter, or am I starting an instance everytime I need to run code?

Regards,

Saurabh

[Jan Schulz]

Hi,

On 22 February 2016 at 20:54, <saso...@colorado.edu> wrote:
> I have a general question. So if I try to run code using jupyter_client, am
> I running against a running instance of Jupyter, or am I starting an
> instance everytime I need to run code?

You run it on a kernel which you started (-> `a.start_kernel()`), so
as long as that kernel is alive, you can run code on it (and the
previous defined variables/functions) are available.

Best,

Jan
--
Jan Schulz
mail: ja...@gmx.net

web: http://www.katzien.de

[saso...@colorado.edu]

Hi,

Thanks for the reply. 

I tried using pieces of the code, and see that my code gets stuck on 

msg = kernel.get_iopub_msg()

Is this normal?

Thanks,

Regards,

Saurabh

[MinRK]

On Mon, Feb 22, 2016 at 10:48 PM, <saso...@colorado.edu> wrote:

Hi,

Thanks for the reply. 

I tried using pieces of the code, and see that my code gets stuck on 

msg = kernel.get_iopub_msg()

You will want to call `client.start_channels()` after creating it, to establish the zmq connections.

 

Is this normal?

Thanks,

Regards,

Saurabh

On Monday, February 22, 2016 at 1:04:26 PM UTC-7, Jan Schulz wrote:

Hi,

On 22 February 2016 at 20:54,  <saso...@colorado.edu> wrote:
> I have a general question. So if I try to run code using jupyter_client, am
> I running against a running instance of Jupyter, or am I starting an
> instance everytime I need to run code?

You run it on a kernel which you started (-> `a.start_kernel()`), so
as long as that kernel is alive, you can run code on it (and the
previous defined variables/functions) are available.

Best,

Jan
--
Jan Schulz
mail: ja...@gmx.net
web: http://www.katzien.de

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[Jeff Zhang]

I have the same issue that I could not get the output, does anyone have solution or sample code for that ? Thanks

在 2016年2月23日星期二 UTC+8下午4:46:30，Min RK写道：

[MinRK]

Here’s a script that runs some code with execute_interactive and captures various outputs.

-Min

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[Ariel Balter]

Here is a simple jupyter_client wrapper for playing around:

https://gist.github.com/abalter/9786332199806a03961f06da9861edf6

 

[matthias...@gmail.com]

and here another demonstration in a notebook ...

https://gist.github.com/MMesch/34515fc35da02a282860c61e56a6861f