Configure your service in spring as you would any other RemoteExporter:

[Dennis Gearon]

That line does not help me much, since I'm new to deep java programming. I have looked, and I can't tell which file I would put that in, i.e. from the following page:

http://code.google.com/p/jsonrpc4j/

this code section:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://www.springframework.org/schema/beans
                http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">

    <bean class="org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/>

    <bean id="userService" class="com.mycompany.UserServiceImpl">
    </bean>

    <bean name="/UserService.json" class="com.googlecode.jsonrpc4j.spring.JsonServiceExporter">
        <property name="service" ref="userService"/>
        <property name="serviceInterface" value="com.mycompany.UserService"/>
    </bean>

</beans>