c=IN IP4 not charge
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Angelo Delphini (Professor Delphini)
Oct 10, 2025, 11:42:05 AM10/10/25
to ivozprovider-users
"Hello everyone! I need help to solve this:"
INVITE sip:015114...@10.255.240.111:5060; "(this is correct)."
From: <sip:19343...@10.17.186.98> "(this is correct)."
To: <sip:015114...@10.255.240.111:5060; "(this is correct)."
Contact: <sip:19343...@10.17.186.98:5060; "(this is correct)."
c=IN IP4 10.17.186.98 "(this is correct)."
"However:"
c=IN IP4 201.XXX.XXX.254 "(My Users Proxy IP, I couldn't manipulate
this. However, I receive the correct information above the PBX, I am using a Retail type account."
"Thank you all!"
INVITE sip:015114...@10.255.240.111:5060; "(this is correct)."
From: <sip:19343...@10.17.186.98> "(this is correct)."
To: <sip:015114...@10.255.240.111:5060; "(this is correct)."
Contact: <sip:19343...@10.17.186.98:5060; "(this is correct)."
c=IN IP4 10.17.186.98 "(this is correct)."
"However:"
c=IN IP4 201.XXX.XXX.254 "(My Users Proxy IP, I couldn't manipulate
this. However, I receive the correct information above the PBX, I am using a Retail type account."
"Thank you all!"
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