Quantum Loopover puzzle

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Melinda Green

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Apr 10, 2025, 5:00:09 PMApr 10
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Hello folks, I'm glad to see some activity in the group again!

The discord discussion of Roice's systolic puzzles got me thinking about puzzles with similar dynamics, so I thought I'd test out the simplest version I could think of which you'll find here:
https://superliminal.com/misc/Quantum%20Loopover.html
To make it, I started by telling the Claude AI what I wanted, and it got it nearly right the first time! I also asked it to come up with a name, and this is the result. I quickly hit its free usage caps while iterating, so I started over with ChatGPT where I have a subscription, and this is the result. It still needs log files and bug fixes, but it's good enough to find out whether the idea is promising.

Please help us find out how difficult it is and share any other ideas you have. I don't believe anyone has solved it yet, so maybe that could be you? Good luck!

-Melinda

Jimmy HUGUET

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Apr 11, 2025, 9:28:47 AMApr 11
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Hey,

That was pretty fun, I manage to solve it. Took me longer than I expected. My strategy was the following:
- First make a single row ABCD, it will also solve the third row IJKL
- Then I found two algorithm that rotate the other two rows around. Here is the notation I'll use: R1 = move the first row one cell to the right, R1' = to the left, C1 = the first column down, C1' = up, R2 the second row, C2 the second columns.
* First algorithm: (C1 R2 R2 C1') R2' (C1 R2 R2 C1') R2' => This invert in pairs the other two rows: E <=> M, F <=> P, H <=> N, G <= O
* Second alg: (C1 C2) R1 (C1' C2') R2 => This rotate in group of three the other two rows, F and M stay in place, E => O => G => E, H => P => N => H

Thanks for a fun puzzle

Suqin Tan

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Apr 11, 2025, 9:30:42 PMApr 11
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My son Christoph was able to solve it too. He said it was very fun and quite hard too, especially the first step. I am trying to ask him to summarize his solution. 

Thanks for the fun puzzle! He used to play loop over a lot and now he had a new challenge.  

Suqin  

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