On Wed, Feb 20, 2019 at 4:59 AM Peter Hancock <
postm...@hbb98.plus.com> wrote:
> Well, I'll have a look at the arxiv paper, but I'm a bit puzzled that
> you say ZF doesn't prove uncountable regulars exist!
> The first one is aleph_1, or perhaps I should say beth_1, or rather
> I should say ZF + GCH. Sorry for any such sloppiness. (I'm not a set-theorist...)
The statement that aleph_1 is regular is the statement that a
countable union of countable sets is countable, which is unprovable in
ZF. The standard proof uses countable choice (though the statement
itself is, I believe, weaker than full countable choice).
More generally, in "All uncountable cardinals can be singular" (Israel
J. Math. (1980) 35: 61), Gitik constructed a model of ZF in which
aleph_0 is the only infinite regular cardinal, under the assumption
that ZFC is consistent with the existence of arbitrarily large
strongly compact cardinals.
Of course a countable *disjoint* union of countable sets is always
countable. That seems to be the notion of "regularity" that you're
capturing with W, but it's not the set-theoretic one.
> Or could I just define a cardinal to be an ordinal not 1-1 with any smaller ordinal?
>
> (Another sloppiness I am prone to is saying, eg, "inaccessible" when I
> should say "weakly inaccessible".)
>
> As for "W" encoding "the step to the next regular", let's suppose that
> the family { B a | a : A } consists of all the regulars we have defined
> so far. Then the tree's inhabiting W A B are closed under all suprema
> of sequences indexed by any (B a). So W A B is "regular" and above B a,
> and the least such. Form now {B' a' | a' : A + 1} by adjoining W A B to B.
> If our starting family was { 0, 1, Nat } , we are now stepping through
> the regular cardi9nals/ordinals w_1, w_2, w_3, ... .