ham_u32_t envFlags = (HAM_ENABLE_RECOVERY | HAM_ENABLE_TRANSACTIONS | HAM_ENABLE_FSYNC);I went to Windows 7 64bit Task Manager and killed (end task) the database accessing program.
ham_u32_t envFlags = (HAM_ENABLE_RECOVERY | HAM_AUTO_RECOVERY | HAM_ENABLE_TRANSACTIONS | HAM_ENABLE_FSYNC);
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Thank you for letting me know, that you can reproduce the issue. This saves me some time :-)
Just because I am curious: The key-record pair that was about to be inserted would first be put in the journal? And there might be up to 16 insert transactions in the journal. How many transactions will be lost by the "corrupted" journal?
I hope my question is not to basic to be asked in this forum...
Thanks for your quick reactions.