GRB.OPTIMAL =2 when model is infeasible?

[Bryce Stansfield]

Basically, I'm running a model atm that's infeasible, as confirmed by the print out:

But immediately after that I printed out the GRB.OPTIMAL code (as seen on the bottom of the screenshot), and it was 2???

Does anyone have any idea why this is happening?

[Ed Rothberg]

GRB.OPTIMAL is a constant; it is always equal to 2.  You should be looking the Status attribute.  Consult any of the examples to see how to do this.