About 2T(n/2) + nlgn

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Haidong (Haydon) Xue

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Jul 1, 2012, 10:52:24 AM7/1/12
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It is maybe a common question about why we cannot use Master Theorem on 2T(n/2) + nlgn 

Since you see:
f(n)=nlgn
g(n)=n
f(n) = Omega(n)

And here is why:
Following the third rule of Mater Theorem, f(n) has to be lower bounded by n^(1+x), x>0, and you can never found a x that:
nlgn =  Omega (n^(1+x))
so, you cannot use Mater Theorem. 


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Haidong(Haydon) Xue
Ph.D Candidate
Research Assistant, Teaching Instructor
Department of Computer Science
Georgia State University

Charles Cole

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Jul 1, 2012, 1:23:27 PM7/1/12
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Haidong (Haydon) Xue

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Jul 1, 2012, 5:44:55 PM7/1/12
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As I said in a previous message, we will have no class on July 4th too. I may update our schedule later.
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