Can we intercept an incoming grpc request (Java ) and send the response back gracefully

[anu....@gmail.com]

Hi Friends,

We have gRPC server which receives the request, and based upon one specific validation, we want to return the request without sending it to service.

We implemented the below class..

public class MyInterceptor implements ServerInterceptor {

    @Override

    public <ReqT, RespT> ServerCall.Listener<ReqT> interceptCall(

            ServerCall<ReqT, RespT> call, Metadata headers, ServerCallHandler<ReqT, RespT> next) {

       if(!someCondition) {

         call.close(Status.UNKNOWN, headers);

         return new ServerCall.Listener<ReqT>() {};       

       

       }

        return next.startCall(call, headers);

    }

} 

the problem with this code is that, at client end it gives the below error trace..

Exception in thread "main" io.grpc.StatusRuntimeException: UNKNOWN

can we send the proper response with error code so that client will get specific error code and not the above error message

Thanks in advance for your help and advice.

Regards

Anurag

[Carl Mastrangelo]

That sounds right.  You should really include an error message along with your status, but that is the way I would go about it.  I vaguely recall gRPC (the library) doing the same thing, but I can't find it at the moment.

[Anurag Misra]

Thanks Carl . If you find something, pls let us know.

Regards

Anurag