[Java] Creating a copy of a Vertex

[Mark McKnight]

Hi all,

At a point in my application I need to send a copy of a Vertex with some properties excluded to another method.  

I haven't found a way to clone a Vertex or create a copy without creating a new graph first which seems wasteful.

Is there a better way to do this that I am missing?

Here's some code:

if (hasPrivate) {

TinkerGraph copyGraph = new TinkerGraph();

Vertex vertexCopy = copyGraph.addVertex(v.getId());

for (String key : v.getPropertyKeys()) {

if (! key.startsWith("private")) {

vertexCopy.setProperty(key, v.getProperty(key));

}

}

vertices.add(vertexCopy);

} else {

vertices.add(v);

}

Thanks,

Mark.

[Alfredo Serafini]

sorry i don't think i correctly understand the question: why can't you do the same on your real graph?

[Mark McKnight]

Well, one reason is that would trigger an unwanted onVertexAdded event.

I've thought it over and think I may be going about the whole process wrong.  I need to present different views of the graph to different users: hiding certain elements or element properties based on the user's privileges.

I think I should be using pipes to send a filtered graph on to the client.  Can anyone point me in the right direction?

Mark.

[pShah]

Does it have to be a Vertex??

If not you can create your class.

To copy the the properties use com.tinkerpop.blueprints.util.ElementHelper.getProperties

Using Guava filter the keys:
Maps.filterKeys(properties, Predicates.not(Predicates.in(reservedProperties)))

[Stephen Mallette]

Not completely sure what you are trying to accomplish, but it sounds
like you want to create a subgraph of some sort. Not sure if you need
to drop down to the Pipes level for what you are doing, but I
typically write some Gremlin to write graph elements to an in-memory
TinkerGraph. From there, there are lots of options: dump the whole
subgraph to GraphML, execute localized Gremlin against the
TinkerGraph, etc.

Stephen

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