How do I delete a graph?

[m...@edcast.com]

I am a newb to gremlin-python and want to create a graph and populate it with nodes and edges. Using the default graph 'g' I got an empty graph

I then, mostly by trial and error, learned how to add vertices one at a time by adding iterate();

graph = Graph()

g = graph.traversal().withRemote(DriverRemoteConnection('ws://localhost:8182/gremlin','g'))

g.addV('person').property('name', 'bob').iterate()

g.addV('person').property('name', 'alice').iterate()

The problem is that my trial and error process added multiple duplicates:

print g.V().toList()

[v[0], v[16], v[2], v[18], v[4], v[20], v[6], v[8], v[10], v[12], v[14]]

My question is: how do I clear the graph? I could find no way of doing it from python.

thanks

[Robert Dale]

Gremlin Server doesn't provide a way to drop graphs.  You can delete all the data in a graph.  g.V().drop().iterate()

Robert Dale

--
You received this message because you are subscribed to the Google Groups "Gremlin-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email to gremlin-user...@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/gremlin-users/5b7021f8-7992-4f72-a98d-8acc322036c7%40googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

[m...@edcast.com]

Thanks!

On Thursday, March 28, 2019 at 9:04:41 AM UTC-7, Robert Dale wrote:

Gremlin Server doesn't provide a way to drop graphs.  You can delete all the data in a graph.  g.V().drop().iterate()

Robert Dale

On Thu, Mar 28, 2019 at 11:59 AM <m...@edcast.com> wrote:

I am a newb to gremlin-python and want to create a graph and populate it with nodes and edges. Using the default graph 'g' I got an empty graph

I then, mostly by trial and error, learned how to add vertices one at a time by adding iterate();

graph = Graph()

g = graph.traversal().withRemote(DriverRemoteConnection('ws://localhost:8182/gremlin','g'))

g.addV('person').property('name', 'bob').iterate()

g.addV('person').property('name', 'alice').iterate()

The problem is that my trial and error process added multiple duplicates:

print g.V().toList()

[v[0], v[16], v[2], v[18], v[4], v[20], v[6], v[8], v[10], v[12], v[14]]

My question is: how do I clear the graph? I could find no way of doing it from python.

thanks

--
You received this message because you are subscribed to the Google Groups "Gremlin-users" group.

To unsubscribe from this group and stop receiving emails from it, send an email to gremli...@googlegroups.com.

[Stephen Mallette]

Just to add a little additional context. Note that you can chain your mutations so that:

g.addV('person').property('name', 'bob').iterate()

g.addV('person').property('name', 'alice').iterate()

can become:

g.addV('person').property('name', 'bob').

  addV('person').property('name', 'alice').iterate()

and thus be one request. Also, clearing a graph is as simple as Bob's answer with g.V().drop() and fine for your situation with your tiny graph that you were playing around with. However, clearing a large graph should not typically be done that way. Always look at the graph database you are using and consider its native methods for dropping/clearing a graph (which may not have python based methods for doing so)

To unsubscribe from this group and stop receiving emails from it, send an email to gremlin-user...@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/gremlin-users/b83b5dbf-e40e-444e-a285-f82f5bd7144d%40googlegroups.com.