How to get the id, the label and all properties from a vertex in one query?

[christophe...@gmail.com]

Hello,

I am using AWS Neptune with gremlin and I want to get the id of a vertex with all properties of the vertex in one query. How can I do this?

I have tried

g.V().hasLabel('file').valueMap(true) 

but the output is:

{ "fileSize": [ "9170" ], "Gremlin.Net.Process.Traversal.T": "f1fce58306f85ca7050503160640d735c9919c8fc85881d65de80bfe31b5ca24", "mimeType": [ "text/html" ] }

No label and no id is there. The problem with

project('id','label',' fileSize', 'mimeType', 'malwareSource').
    by(id).
    by(label).
    by('fileSize').
    by('mimeType').
    by('malwareSource') 

is that the propertie malwareSource is sometimes part of a file vertex an sometimes not. So if there is no malwareSource property an exception is thrown.

[Stephen Mallette]

Answered on SO: 

https://stackoverflow.com/q/55495060/1831717

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[christophe...@gmail.com]

The answer on SO did not fix the problem.

Am Donnerstag, 4. April 2019 13:03:26 UTC+2 schrieb Stephen Mallette:

Answered on SO: 

https://stackoverflow.com/q/55495060/1831717

On Thu, Apr 4, 2019 at 4:09 AM <christophe...@gmail.com> wrote:

Hello,

I am using AWS Neptune with gremlin and I want to get the id of a vertex with all properties of the vertex in one query. How can I do this?

I have tried

g.V().hasLabel('file').valueMap(true) 

but the output is:

{ "fileSize": [ "9170" ], "Gremlin.Net.Process.Traversal.T": "f1fce58306f85ca7050503160640d735c9919c8fc85881d65de80bfe31b5ca24", "mimeType": [ "text/html" ] }

No label and no id is there. The problem with

project('id','label',' fileSize', 'mimeType', 'malwareSource').
    by(id).
    by(label).
    by('fileSize').
    by('mimeType').
    by('malwareSource') 

is that the propertie malwareSource is sometimes part of a file vertex an sometimes not. So if there is no malwareSource property an exception is thrown.

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To unsubscribe from this group and stop receiving emails from it, send an email to gremli...@googlegroups.com.

[Stephen Mallette]

i updated the answer based on your comments. perhaps you had not seen that yet.

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