Google+ Photo - unable to sync/download files | Google takeout

[Jakub Muszynski]

Hi

I'm trying to get copy of my data - photos upload to Google+ Photo via

https://www.google.com/settings/takeout/downloads

When I do create custom archive, containig "Google Photos" it works for a while, and display under "My archives" 

"Archive for one Google serivice - less than 1Mb", although there are about 3GB of photos, and it's not "downloadable",

Any ideas how can I get my data?

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What I would like to achieve:

I would like to sync _automaticaly_ my Android phone with my PC. It would be nice, if I could have photos in cloud like Google+ Photos.

Previously I was using Ubuntu One, but it's going to end it's service. I tought GoogleDrive / GoogleCloud would be nice replacment, but currently I can sync phone with cloud, but I don't see an option for sycn cloud -> Ubuntu.

I would like not to use another service, since there are too many accounts to manage, but I know that DropBox would do what I need :/

[Jakub Muszynski]

Well, I haven't find any proper way to sync Google+ Photo yet, I did move to DropBox, but it's not perfect (it does rename filenames, i need oryginal name, so here is quick rename script)

Anyway, I think of moving to OwnCloud

https://github.com/owncloud/core/wiki/Ubuntu-One-Migration

http://www.muktware.com/2014/04/ubuntu-one-users-can-migrate-open-source-owncloud/25020

since you data is 100% private (if you use own hosting), and there are no problems with file sync or file renaming....

The script

#less pychange.py :

#!/usr/bin/env python

import os

files=(os.listdir('.'))

#Current file format: 2014-03-22 14.32.49.jpg

#Expected file format: 2014-03-22_143249.jpg

for myFile in files:

    if " " in myFile:

        date,hour = myFile.split(" ")

        if len(hour.split('.')) == 4:

            hourNew = hour.split('.')[0] + hour.split('.')[1] + hour.split('.')[2] + '.jpg'

            print "%s %s %s" % (date,hour,hourNew)

            newName = date + '_' + hourNew

            print newName 

            os.rename(myFile, newName)