Remove multiple labels - need help to customize a script

[Tamara Strelnykova]

Hi everyone!

I really need your help to customize a script.
I've been using a poplular script to remove 1 label for the optimization process and it works perfectly. The problem is now I have 12 labels and I want one script to remove all of them. 
My labels are ['ROI -100', 'ROI -20-0', 'ROI -75-50', 'ROI -99-75', 'ROI 0-50', 'ROI 200-300', 'ROI 300-400', 'ROI 400-600', 'ROI 600-800', 'ROI 800-1000', 'ROI-50-20', 'ROI 0-50'].

The perfect script would remove all labels that contain word 'ROI'.

The script I'm using:

function main() {

    

    var DEL_LABEL = 'ROI 0-50';

    

    var keywordIterator = AdsApp.keywords()

    .withCondition("LabelNames CONTAINS_ANY ['ROI 0-50']")

    .get();

    while (keywordIterator.hasNext()){

      var keyword = keywordIterator.next()

      var labelIterator = keyword.labels().get()

      while (labelIterator.hasNext()){

        var label = labelIterator.next()

        var labelname = label.getName()

        Logger.log("labelname: "+labelname)

        if (labelname = DEL_LABEL) {

          keyword.removeLabel(DEL_LABEL)

        }

      }

    }

    

     }

I would be grateful for any suggestions!

[cwlind]

Would something like this work?

function main() {
   
    var DEL_LABEL = 'ROI';  //changed from ROI 0-50
   
    var keywordIterator = AdsApp.keywords()
    .withCondition("LabelNames CONTAINS_ANY ['ROI']") //changed from ROI 0-50
    .get();

    while (keywordIterator.hasNext()){
      var keyword = keywordIterator.next()
      var labelIterator = keyword.labels().get()
      while (labelIterator.hasNext()){
        var label = labelIterator.next()
        var labelname = label.getName()
        Logger.log("labelname: "+labelname)

        if (labelname.startsWith(DEL_LABEL)) {  //if the label starts with ROI, remove it
          keyword.removeLabel(labelname)
        }
      }
    }
   
     }

The above will *should* remove all labels starting with 'ROI'. I say *should* because I have not tested this.

[Tamara Strelnykova]

Thanks for your suggestion! I've tried it, but unfortunately it runs with no changes :(

[cwlind]

Ok, I wasn't sure. What if iterate over each Label instead? Something like:

function main() {

    var DEL_LABEL = ['ROI -100', 'ROI -20-0', 'ROI -75-50', 'ROI -99-75', 'ROI 0-50', 'ROI 200-300', 'ROI 300-400', 'ROI 400-600', 'ROI 600-800', 'ROI 800-1000', 'ROI-50-20', 'ROI 0-50'];

    for (var i = 0; i < DEL_LABEL.length; i++) {

        var keywordIterator = AdsApp.keywords()
            .withCondition("LabelNames CONTAINS_ANY ['" + DEL_LABEL[i] + "']")


            .get();
        while (keywordIterator.hasNext()) {
            var keyword = keywordIterator.next();
            var labelIterator = keyword.labels().get();
            while (labelIterator.hasNext()) {
                var label = labelIterator.next();
                var labelname = label.getName();


                Logger.log("labelname: " + labelname);
                if (labelname == DEL_LABEL[i]) { //remember to use 2 == to check equality
                    keyword.removeLabel(DEL_LABEL[i]);
                }
            }
        }
    }
}

[Tamara Strelnykova]

It worked! Thank you so much for your help!