How to check users that have logged in?

[Beloit Manager]

 Google API experts,

  We want to run a report of all users that have logged in or not logged in, what is the easiest way to do this?  We have found the agreedToTerms attrtribute in the users.entry download, but we don't see any values for any of them.  So we are not sure that we can use that or must use something else.  We are trying to do this using the Python API's.  Can someone give us advice?

  Tim

[Alexandre Jacquet]

Hello Beloit,

I think best way is using Report API, there you can get the firstLogin and the lastLogin, instead of validating the hasAgreedToTerms attribute, 

http://code.google.com/intl/en/googleapps/domain/reporting/google_apps_reporting_api.html#Accounts_Report

date, account_id, account_name, status, quota_in_mb, 
    usage_in_bytes, primary_account_id, primary_account_name, creation_date, 
    last_login_date, last_web_mail_date, surname, given_name,
    service_tier, channel, suspension_reason, last_pop_date, creation_time,
    last_login_time, last_web_mail_time, last_pop_time

20060808, 000000aaaaa11111, "ab...@example.com", "ACTIVE", 10240, 
    9235, , , 20060802, 19691231, 20060802, , "Abuse", 0, , , 20060802,
    2006-08-02 17:22:15, 1969-12-31 16:00:00, 2006-08-02 17:22:15, 2006-08-02

                                                                                           

Alexandre Jacquet Google Apps Deployment Specialst  São Paulo | SP | Brasil Tel.: 55 11 8064 6882

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[NCCFred]

Hello,

 

Using the Reporting API, I check to see if the last_login_date = '19691231', if it does then the user never accessed the account via the web interface.

 

Hope this helps.

 

Fred

[Beloit Manager]

Okay, How do I get the created_date attribute from the report? I am trying to create an automated python script to check if any of the accounts are not logged in. I guess I am kind of looking for a similar approach as the

if user_entry.report.created_date == '19691231:
    #never logged in

I looked around for some python documentation but did not have any success.

-DN