Firebase Cloud functions express ip location

[renaud hedde]

Hi,

I'm working on cloud function projet with nodejs express

I'm trying to get the request user city location.

My request coming from france but every test I get the google US "mountain view" location....

I'm trying 3 differents technique to get ip

• req.connection.remoteAddress
• x-appengine-user-ip
• x-forwarded-for

Also  I config express with app.set('trust proxy', true);

But anycase I got google server IP instead request user ip ?

many thanks

renaud

[gjs]

Hi,

Try examining request headers eg

header X-AppEngine-Country = AU
header X-AppEngine-City = sydney

Regards

[renaud hedde]

Ok,

After read cloud function request['header']

x-forwarded-for, fastly-client-ip display my ipAdress, good !

I test my ip with https://ipinfo.io and my city display, good as well ! 

However google cloud functions

X-AppEngine-Country is still US, bad :(

I don't understand why google don't use x-forwarded-for and/or not able to located my ip (maybe google IP database is not updated ?)

best regards 

renaud

[Prashanth Acharya]

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[Sam (Google Cloud Support)]

Hi, as already noted, 'fastly-client-ip' is the header to use. According to this Stackoverflow post [1], the Firebase Cloud Functions docs points to using 'fastly-client-ip' [2]. 

Google Cloud Platform is a different platform for Cloud Functions which runs in App Engine, see this Stackoverflow post [3]. So if you are using a Firebase Cloud Function then using the 'x-forwarded-for' or 'fastly-client-ip' should be the headers to use.

[1] https://stackoverflow.com/a/51850187

[2] https://www.npmjs.com/package/request-ip#how-it-works

[3] https://stackoverflow.com/a/37530362