Handling File Uploads

[crazywizard]

I need to handle uploaded files on my server. Problem is, the uploads
come from other user applications that I have no control over. My
problem centers around how to get the uploaded file without
referencing or knowing the index/key name of the file.
My app engine python code:
file=self.request.POST['file']

As you can see, I have to explicitly define the key name as 'file'.
However, the uploading application doesn't have this defined.
Pys60 code:
conn=httplib.HTTPConnection("www.myserver.com")
conn.request("POST", "/upload", 'file")

This only defines the method, destination, and file object. How can I
still get the POSTED file?
Please do not ask me to change or manipulate the client upload
procedures/functions because I don't have access to them.!

[Nick Johnson (Google)]

Hi,

In the example below, the file isn't being uploaded as part of a form - it's simply the contents of the request body. You can access it with self.request.body.

-Nick Johnson

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[Tim]

On the topic of file uploads (if you'll pardon slight hijacking of the thread), when using the provided webapp framework, I couldn't find a way to get hold of the type and filename parameters from a file submitted as part of a multipart form request, so had to resort to a "plain CGI" handler

def main():

    form = cgi.FieldStorage()

    if "uploadedfile" in form:

        i = form["imagefile"]

        filename = i.filename

        filetype     = i.type

        filecontents  = i.value

No great hardship (and I expect these extra values can't always be trusted - I only use them as part of reporting back to the user what's been done), but does anyone know how to get these values using webapp, or do I have to leave this page as it stands?

--

T

[Nick Johnson (Google)]

http://blog.notdot.net/2009/9/Handling-file-uploads-in-App-Engine

-Nick

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[Tim]

Thanks for that Nick.

Seems I must have been sleeping when looking at that part of the webapp docs - getting the appropriate field from the request.POST

  file = self.request.POST["filefield"]

  

gets me an object with properties "filename" and "type" and "value" (for the actual decoded data) - Nick's blog post then shows how to store this in the datastore.

Apologies for being so thick

--

Tim

[David Ngugi]

Hi NIck, if I do self.request.body, I also get a lot of meta-data
attached to the file's contents which I don't want. Is it possible to
just get the file part only?

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[Nick Johnson (Google)]

Hi David,

What does this metadata look like? If it's HTTP-style headers, then it probably _is_ a multipart form, and you should be handling it in the standard way, using self.request.POST or self.request.get().

-Nick