Now it seems to work fine, but ... if I want to represent watts ... versus total watts ... how can I do it?
A graphic of this styleor against time, but in the same style as the PDC
Now it has returned to seem not to work
Currently I have it as you indicated to meBut one of the expressions that I don't quite understand is the power performed by each leg. I guess it comes from samples(POWER)*samples(BALANCE). But how do we differentiate the right leg from the left?
Better?
Great,I would like to share this graphic in the cloud, but I would like to know if it is all right and makes sense.
One thing I don't quite understand is the purple dots that appear diagonally. What is it?
I don't know why, but it won't let me attach the .gchart file
xx <- samples(POWER);
yy <- curve(GPRL,y)-samples(POWER)*samples(BALANCE)/100;
yy <-yy[>0];
annotate(label, "GPAL avg", round(mean(yy)));
??xx <- samples(POWER);
yy <- curve(GPRL,y)-samples(POWER)*samples(BALANCE)/100;
yy <-yy[>0];
annotate(label, "GPAL avg", round(mean(yy)));
??
Something I did wrong with the first post.
Here again my assumption in addition.
For the left leg. Very roughly.
Drive power left=Power*BALANCE*LEFTEFFECTIVENESS
Is the power that moves you forward.
BALANCE indicates the performance distribution and LEFTEFFECTIVENESS how efficient the process is. The efficiency (LEFTEFFECTIVENESS) is not always 100%, the result of Power*BALANCE*LEFTEFFECTIVENESS must be < Power*BALANCE.
Power loss left=Power*BALANCE*(100-LEFTEFFECTIVENESS)
Is the power that works against the propulsion on. That's why I have shown it negatively in the chart.
Both formulas together give the power for the left leg.
Power*BALANCE*LEFTEFFECTIVENESS+Power*BALANCE*(100-LEFTEFFECTIVENESS)
The sample whether the assumption is correct.
Power*BALANCE=Power*BALANCE*LEFTEFFECTIVENESS+Power*BALANCE*(100-LEFTEFFECTIVENESS)
Then I filtered all values at BALANCE which are negative. There I do not know, if this makes sense.
Do not understand the formula from the PDF.
If I understand the PDF correctly:
GPR=P+
GPA=P-
--> GPR+GPA=total Power
--> (GPR+GPA)/total Power=<1
When I calculate this with numbers I come to this:
total power=268 W; balance=0.54;
torque effectiveness L= 95; torque effectiveness R = 78
GPRL=(total Power *balance*100)/torque effectiveness L
GPRL=(268*0.54*100)95=152.34 W
GPRR=(total power *(1-balance)*100)/torque effectiveness R
GPRR=(268*(1-0,54)*100)78=158,05 W
GPAL=(total power *balance*100)/torque effectiveness L-total power *balance
GPAL=(268*0,54*100)95-268*0,54=7,61 W
GPAR=(total power *(1-balance)*100)/torque effectiveness R-total power *(1-balance)
GPAR=(268*(1-0,54)*100)78-268*(1-0,54)=34,77 W
GPR+GPA=GPRL+GPRR+GPAL+GPAR=152,34+158,05+7,61+34,77=352,77 W
(GPR+GPA)/total Power=352,77/268=1,32
--> 132 %
If I see GPR as usable power and GPA as non-usable power and total power as supplied power.
I cannot make the GPR+GPA greater than total power.
I am looking for information to complement the graph. My idea would be to add the Kurtotic index, which is the ratio between the maximum effective force produced on the pedal and the average effective force in each pedal stroke. The lower the value of this index, the better pedaling technique. But I can't find the mathematical expression.Do you have some information about this?
El sábado, 24 de octubre de 2020, 16:21:17 (UTC-3), Valvero escribió:I am looking for information to complement the graph. My idea would be to add the Kurtotic index, which is the ratio between the maximum effective force produced on the pedal and the average effective force in each pedal stroke. The lower the value of this index, the better pedaling technique. But I can't find the mathematical expression.Do you have some information about this?No
I've tried this, but it doesn't seem to show anything