how to declare type as interface{}

[Alexander Mills]

This works:

var z interface{}
if err := json.NewDecoder(resp.Body).Decode(&z); err != nil {
     t.Fatal(err)
}

but this doesn't work:

if err := json.NewDecoder(resp.Body).Decode(&interface{}{}); err != nil {
     t.Fatal(err)
}

and this doesn't work:

if err := json.NewDecoder(resp.Body).Decode(&struct{}{}); err != nil {
     t.Fatal(err)
}

my goal is to unmarshal to an anonymous variable and discard it, as part of a test. Is there a way to do this?

[Axel Wagner]

What's wrong with the first one?

The second one doesn't work because there are not interface composite literals. So you need to actually have an interface{} variable to take the address of.

The third one seems to work just fine: https://play.golang.org/p/zn2mL69VzPo

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[Brian Candler]

You can't take the address of an arbitrary value or expression, although you can for composite literals which is why &struct{}{} is OK.

https://golang.org/ref/spec#Address_operators

[Harald Weidner]

Hello,

> but this doesn't work:
>
> if err := json.NewDecoder(resp.Body).Decode(&interface{}{}); err != nil {
> t.Fatal(err)
> }

You can use new(interface{}).

See https://play.golang.org/p/s85MwlDygBG

Harald