Replace all verbs in Printf format to %v

[Archos]

I've a string with the verb's format for Printf, and I would want to
convert to %s (because I've each into string)

===
package main

import (
"fmt"
"regexp"
)

var value = "\"(%d, %d) = %d\\n\""

func main() {
// The idea is replace [bcdefgopqstvxEGTUX] by 'v' after of be
matched
reVerb := regexp.MustCompile(`[^\\]%[+\-# 0]?([bcdefgopqstvxEGTUX])`)

r := reVerb.ReplaceAllString(value, "v")
fmt.Println(value)
fmt.Println(r)
}
===
But the result isn't what I was expecting

"v,v) =v\n"

[Archos]

Sorry! That doesn't solve my problem.

I've to split the string in each verb

[Jan Mercl]

This works in the limited case where %% is not present. Note: \% is not a valid escape seq.

package main

import (

        "fmt"

        "regexp"

)

var value = "\"(%d, %d) = %d\\n\""

func main() {

        reVerb := regexp.MustCompile(`%[+\-# 0]?([bcdefgopqstvxEGTUX])`)

        r := reVerb.ReplaceAllString(value, "%v")

        fmt.Println(value)

        fmt.Println(r)

}

12:05 myname@tux64:~/tmp/go$ make && ./tmp 

6g   -o _go_.6 tmp.go 

6l  -o tmp _go_.6

"(%d, %d) = %d\n"

"(%v, %v) = %v\n"

12:05 myname@tux64:~/tmp/go$

[Archos]

On Dec 31, 11:06 am, Jan Mercl <jan.me...@nic.cz> wrote:
> This works in the limited case where %% is not present. Note: \% is not a
> valid escape seq.

That's my failure. I was using [^\\] to skip verbs like `\%s` but I
see that it isn't valid.

[Sol Toure]

 It is valid. But since regexp does not support expressions such as $1 or \1 you need to use "regexp.ReplaceAllStringFunc" instead.

Your replacement become:
r := reVerb.ReplaceAllStringFunc(value, func(s string)string{return string(s[:len(s)-1])+"v"})

[Kyle Lemons]

You need to do more than just s/%./%v/ to get a proper translation.  Things like %q and %.5f have very specific meanings that you will break.  The quoted-string verb, in particular, is important and not maintaining its semantics could introduce security issues.