Converting a Byte to an array of bits

[kyl...@gmail.com]

For an application I need complete access to the bits of a byte and therefore would love an efficient way to get an array of zeroes and ones packaged in an array.

Would there be a simple method to do this in go that would be efficient? I'd prefer not to have to roll my own system because speed is desired.

Thanks!

[Michael Jones]

do you want something more than:

var theByte uint8

var theArray [8]uint8

// expand

for bit, mask := 0, 1; bit < 8; bit, mask = bit++, mask <<= 1 {

    if theByte & mask != 0 {

        theArray[i] = 1

    }

}

// process

// ...

// contract

theyByte = 0

for bit, mask := 0, 1; bit < 8; bit, mask = bit++, mask <<= 1 {

    if theArray[i] != 0 {

        theByte |= mask

    }

}

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Michael T. Jones | Chief Technology Advocate  | m...@google.com |  +1 650-335-5765

[Kevin Gillette]

The thing is that an array of bits is not going to be the most efficient way to access individual bits in a byte, not to mention, it's fairly trivial to retrieve individual bits with bit-ops anyway: http://play.golang.org/p/D7nJsWtcFt