How to fill HTTP request post form info?

[Andy W. Song]

Sorry for asking this maybe silly question:

Please see below snippet. Basically I want to send a POST but don't know how to fill the form. According to http://weekly.golang.org/pkg/exp/html/ http client will ignore request.Form and use Body. Then how do I put my form info into Body?

    conn, err := net.Dial("tcp", "someURL:80")

    if err != nil {

        panic(err)

    }

    c := httputil.NewClientConn(conn, nil)

    r, _ := http.NewRequest("POST", "http://someURL/post.php", nil)

    // Need to fill the form info here

    r, _ := c.Do(r)

Thanks

Andy

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[Jarod Liu]

example from http package doc http://golang.org/pkg/net/http/

resp, err := http.PostForm("http://example.com/form",
	url.Values{"key": {"Value"}, "id": {"123"}})

[Andy W. Song]

I was intended to use low level httputil.ClientConn.Write() so that I can have more control over the behavior. So my question is how to manually compose the request body.

Thanks

Andy

[Andy W. Song]

Documents says the client will ignore this field. 

    // Form contains the parsed form data, including both the URL
    // field's query parameters and the POST or PUT form data.
    // This field is only available after ParseForm is called.
    // The HTTP client ignores Form and uses Body instead.
    Form url.Values

On Sat, Apr 7, 2012 at 11:15 AM, Jarod Liu <liuyu...@gmail.com> wrote:

http://golang.org/pkg/net/http/#Request

there is a Form field in struct Request   

r, _ := http.NewRequest("POST", "http://someURL/post.php", nil)

r.Form.Add("key", "value")

[Jarod Liu]

Yes, sorry. just read the source of func PostForm. That's the way to do it.

http://golang.org/src/pkg/net/http/client.go?s=9035:9114#L292