Convert 8 byte array to int64?

[cthom lists]

This is the solution I've come up with...

import (

        "fmt"

        "encoding/binary"

        "os"

)

type Byte64 [8]byte

func (bits *Byte64) Read(p []byte) (r int, e os.Error) {

        if len(p) > 8 {

                e = os.EOF

        }

        for r = 0; r < 8 && r < len(p); r++ {

                p[r] = bits[r]

        }

        return

}

func main() {

        var n int64

        bits := new(Byte64)

        bits[0] = 1

        bits[1] = 2

        binary.Read(bits, binary.LittleEndian, &n)

        fmt.Printf("%d\n", n) //513

}

Is there an easier way to convert byte arrays to ints, etc?

[peterGo]

cthom,

You could be more concise.

package main

import (
"bytes"
"fmt"
"encoding/binary"
)

func main() {
var n int64

b := [8]byte{1, 2}
buf := bytes.NewBuffer(&b)
binary.Read(buf, binary.LittleEndian, &n)
fmt.Println(n, b)
}

Peter

[Ostsol]

For integer types you could alway just pack the bytes using
bitshifting.

-Daniel