How to import one field from package, etc

[Alex Mills]

Using node.js, we might have this:

const z = new Z();

exports.z = z

and then in another file we can import

import {z} from '../z'

with Golang, I am trying to do something similar:

package log

import Logger "github.com/foo/bar/logger"

// create an instance

var log = Logger.create()

// export the methods

var Info = log.Info

var Warn = log.Warn

var Error = log.Error

and then we import it like 

import "github.com/a/b/log"

func init(){

   log.Info("something")

   log.Warn("something")

}

/// ===========

basically what I am asking is if there is a way to create an instance and access it's methods - so that in my code I don't have to do:

log.log.Info()

but instead I can do:

log.Info()

hope the question makes sense.

[Jason Phillips]

Did you try your own suggestion? It seems to work fine: https://play.golang.org/p/KVo5COKj2ii

[Alex Mills]

It works temporarily, but then I have to manually update each file that imports + exports the methods, it won't "just work" with new versions of the library that gets imported, right?

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[Jason Phillips]

To answer the title question: no, there's no way to limit an imported package to a subset of its exported identifiers. But, given the example provided, it seems the suggested solution works exactly as you desire.

You can give a local identifier to an imported package (e.g. https://play.golang.org/p/WJChIJoMMys ) or you can bring another package's exported identifiers into the current package's scope with "." as a package name (e.g. https://play.golang.org/p/3IyGkPNJZMx ) but I don't think either is what you're asking for.

Can you provide any more context as to what your end goal is and why the using the package name to access your identifiers is a problem?